无法将类 stdClass 的 PHP 对象转换为字符串
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PHP Object of class stdClass could not be converted to string
提问by Ruchika
I have made a small multiplication function
我做了一个小的乘法函数
<p><?php
$a= "<?php echo $this->prodDet->v_price?>";
$b=.26;
$c=$a*$b;
echo $c;
?>
Here the price value is extracted from database of the requiste product and is multiple by fixed .26 variable. Wondering why am getting this errror -
这里的价格值是从需求产品的数据库中提取的，乘以固定的 0.26 变量。想知道为什么会出现此错误 -
Catchable fatal error: Object of class stdClass could not be converted to string in
I am learning the basics of PHP. can someone suggest how to get it solved please?
我正在学习 PHP 的基础知识。有人可以建议如何解决吗？
Thanks
谢谢
回答by bwoebi
You don't know what you're trying here?
你不知道你在这里尝试什么？
$a = "<?php echo $this->prodDet->v_price?>";
$alooks after the assignment like <?php echo <the value of $this->prodDet->v_price>?>. The <?phppart there is not executed. You surely want to write:
$a像<?php echo <the value of $this->prodDet->v_price>?>. <?php那里的部分没有执行。你肯定想写：
$a = $this->prodDet->v_price;
And make sure that $ais not an object at the end! (what you can check via var_dump($a);in the line after the assignment)
并确保它$a最终不是一个对象！（您可以var_dump($a);在分配后的行中检查什么）
回答by Ben
v_pricehas been set as a class instance somewhere before these lines of code. My guess is that happens somewhere in prodDet.
v_price在这些代码行之前的某个地方已将其设置为类实例。我的猜测是发生在prodDet.
So, when you echoit, PHP tries to convert to a string and fails.
因此，当您使用echo它时，PHP 会尝试转换为字符串并失败。
To see what kind of class it is, try:
要查看它是哪种类，请尝试：
var_dump($this->prodDet->v_price);
That will help you debug.
这将帮助您调试。
An example is in PHP: Catchable fatal error: Object of class stdClass could not be converted to string, where the person accidentally sets a variable to be a class in this line:
一个例子是在PHP 中：Catchable fatal error: Object of class stdClass could not be convert to string，其中该人不小心将变量设置为这一行中的类：
$procID = $client->start(array("prefix"=>"Genesis"));
then they try to echo $procIDand get the same error. You can't echo a class because it can't be changed to a string.
然后他们尝试回声$procID并得到相同的错误。您不能回显类，因为它不能更改为字符串。
Also, when you do
另外，当你做
$a = echo ...
$awill not be what you expect, since echojust prints out to the screen! It doesn't return the value. You'll want to remove the echoand just set it directly:
$a不会是你所期望的，因为echo只是打印到屏幕上！它不返回值。您将要删除echo并直接设置它：
$a = $this->prodDet->v_price->getSomeValue();
回答by user3728517
I also get same error message which is
我也收到相同的错误消息
after one hour checking everything i find that i have done some small mistake which is i have use variable sign ($) twice when fetching data. which is
一小时检查完所有内容后，我发现我犯了一些小错误，即我在获取数据时使用了变量符号 ($) 两次。这是
After remove one dollar sign it's working fine,it may be help someone:)
删除一个美元符号后它工作正常，它可能对某人有帮助:)
回答by Andrew Koper
With primitive variable and strings, $name = "Charlie";
使用原始变量和字符串， $name = "Charlie";
Objects store many, related things together. Strings, numbers, booleans, etc are stored as properties of the object. Properties are accessed with the object operator ("arrow operator") like $person->name = "Charlie";
对象将许多相关的东西存储在一起。字符串、数字、布尔值等存储为对象的属性。使用对象运算符（“箭头运算符”）访问属性，如 $person->name = "Charlie";
