c.curCSS 不是 jQuery 的函数错误
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c.curCSS is not a function bug from jQuery
提问by Jozsef Naghi
I am getting this errors message in console.
我在控制台中收到此错误消息。
c.curCSS is not a function
...,m,n){c.each(e,function(){g-=parseFloat(c.curCSS(f,"padding"+this,true))||0;if(m...
This my function who does the autocomplete:
这是我的自动完成功能：
function autocomplete_name (name_val, id_val,action, button) {
$(document).ready(function () {
$(name_val).autocomplete({
source: function( request, response ) {
$.ajax({
url: action,
dataType: "json",
data: {
term: request.term
},
success: function( data ) {
response( $.map( data, function( item ) {
return {
label: item.name,
value: item.name,
id: item.id
}
}));
}
});
},
minLength: 2,
select: function( event, ui ) {
$(id_val).val(ui.item.id);
$(name_val).val(ui.item.value);
$(button).trigger("click")
}
});
});
}
I have jQuery 1.8.3 version and I do not have access to the file. It is from another server, I just use a link to the library. The function works, but there is no css apply to the results and i am getting that error message in console. YES I saw solutions that I have to modified the library, but I do not have acccess to do that.What should I do in order to make this work.
我有 jQuery 1.8.3 版本，但我无权访问该文件。它来自另一台服务器，我只是使用指向库的链接。该函数有效，但没有适用于结果的 css，我在控制台中收到该错误消息。是的，我看到了必须修改库的解决方案，但我无权这样做。我应该怎么做才能完成这项工作。
回答by Frédéric Hamidi
As a workaround, you could simply redefine $.curCSS()in your module.
作为一种解决方法，您可以简单地$.curCSS()在模块中重新定义。
After including jQuery, write something like:
在包含 jQuery 之后，编写如下内容：
jQuery.curCSS = function(element, prop, val) {
return jQuery(element).css(prop, val);
};
jQuery UI will end up calling that function afterwards, and the autocomplete widget will work as intended.
之后 jQuery UI 将最终调用该函数，并且自动完成小部件将按预期工作。
Update:I just realized my answer is a quasi-duplicate of Johann Chaves Saborío's answer there. I will leave it here, though, because my function propagates the return value of $.css()to the caller, but his doesn't.
更新：我刚刚意识到我的答案是 Johann Chaves Saborío 在那里的答案的准重复。不过，我将把它留在这里，因为我的函数将 的返回值传播$.css()给调用者，而他的却没有。
