javascript 字母数字正则表达式javascript
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alphanumeric regex javascript
提问by Saher Ahwal
I am having a problem to get the simple reges for alphanumeric chars only work in javascript :
我在获取字母数字字符的简单 reges 时遇到问题，只能在 javascript 中使用：
var validateCustomArea = function () {
cString = customArea.val();
var patt=/[0-9a-zA-Z]/;
if(patt.test(cString)){
console.log("valid");
}else{
console.log("invalid");
}
}
I am checking the text field value after keyup events from jquery but the results are not expected, I only want alphanumeric charachters to be in the string
我在 jquery 的 keyup 事件之后检查文本字段值，但结果不是预期的，我只希望字符串中包含字母数字字符
采纳答案by Saher Ahwal
I fixed it this way
我是这样修的
var validateCustomArea = function () {
cString = customArea.val();
console.log(cString)
var patt=/[^0-9a-zA-Z]/
if(!cString.match(patt)){
console.log("valid");
}else{
console.log("invalid");
}
}
I needed to negate the regex
我需要否定正则表达式
回答by mu is too short
This regex:
这个正则表达式：
/[0-9a-zA-Z]/
will match any string that contains at least one alphanumeric character. I think you're looking for this:
将匹配任何包含至少一个字母数字字符的字符串。我想你正在寻找这个：
/^[0-9a-zA-Z]+$/
/^[0-9a-zA-Z]*$/ /* If you want to allow "empty" through */
Or possibly this:
或者可能是这样的：
var string = $.trim(customArea.val());
var patt = /[^0-9a-z]/i;
if(patt.test(string))
console.log('invalid');
else
console.log('valid');
回答by Jon Newmuis
Your function only checks one character (/[0-9a-zA-Z]/means onecharacter within any of the ranges 0-9, a-z, or A-Z), but reads in the whole input field text. You would need to either loop this or check all characters in the string by saying something like /^[0-9a-zA-Z]*$/. I suggest the latter.
您的函数仅检查一个字符（/[0-9a-zA-Z]/表示0-9、az 或 AZ 范围内的任何一个字符），但读取整个输入字段文本。您需要循环此操作或通过说出类似/^[0-9a-zA-Z]*$/. 我建议后者。
