bash 在 ShellScript 中根据 Curl 输出分配变量
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In ShellScript Assign Variable Based on Curl Output
提问by Spencer
I am trying to write a shellscript that will assign a variable to curl output. The output of this curl command when I run it from the command line is this:
我正在尝试编写一个 shellscript，它将为 curl 输出分配一个变量。当我从命令行运行 curl 命令时，它的输出是这样的：
$curl "test.test.com/landing/505978290?c=Area%20Rug"
www.test.com/test/test?test=test
Going to this url is supposed to simply output a text document with another url. I want to test that this second url is the url it is supposed to be.
转到这个 url 应该只是输出一个带有另一个 url 的文本文档。我想测试这个第二个 url 是它应该是的 url。
url = $(curl "test.test.com/landing/505978290?c=Area%20Rug")
if [$url -gt "www.tazinga.com/landing/505978290?c=area%20rug&si=gw&alt_css=silver&sv=34&"] echo ""test.test.com/landing/505978290?c=Area%20Rug did not redirect properly"
else
echo "Right URL"
fi
However, when I run the shellscript I get this output:
但是，当我运行 shellscript 时，我得到以下输出：
% Total % Received % Xferd Average Speed Time Time Time Current
Dload Upload Total Spent Left Speed
100 75 0 75 0 0 997 0 --:--:-- --:--:-- --:--:-- 1013
Command not found.
-bash: [: missing `]'
yes
If I try to print out url, I get an empty string. I get this regardless as to whether or not the string correctly matches or not. Why is curl operating differently in a shellscript than from the command line.
如果我尝试打印出 url，我会得到一个空字符串。无论字符串是否正确匹配，我都会得到这个。为什么 curl 在 shellscript 中的运行方式与在命令行中的运行方式不同。
回答by ajreal
There should no have spaces when assign url, try this :-
分配 url 时不应该有空格，试试这个：-
url=$(curl -s ...)
note : curl -s is to suppress the progress meter
注意： curl -s 是抑制进度表
