Java 如何将 2018-04-10T04:00:00.000Z 字符串转换为 DateTime？
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How do I convert 2018-04-10T04:00:00.000Z string to DateTime?
提问by Miguel Barra
I get a date from a JSON API which looks like this "2018-04-10T04:00:00.000Z". I want to convert it in order to obtain a Date or String object and get something like "01-04-2018" that its "dd-MM-YYYY". How can I do it?
我从 JSON API 得到一个日期，它看起来像这样“2018-04-10T04:00:00.000Z”。我想转换它以获得日期或字符串对象并获得类似“01-04-2018”的“dd-MM-YYYY”。我该怎么做？
采纳答案by Tamas Rev
Update: Using DateTimeFormat, introduced in java 8:
更新：使用DateTimeFormat，在 java 8 中引入：
The idea is to define two formats: one for the input format, and one for the output format. Parse with the input formatter, then format with the output formatter.
这个想法是定义两种格式：一种用于输入格式，一种用于输出格式。使用输入格式化程序进行解析，然后使用输出格式化程序进行格式化。
Your input format looks quite standard, except the trailing Z. Anyway, let's deal with this: "yyyy-MM-dd'T'HH:mm:ss.SSS'Z'". The trailing 'Z'is the interesting part. Usually there's time zone data here, like -0700. So the pattern would be ...Z, i.e. without apostrophes.
您的输入格式看起来很标准，除了尾随Z. 无论如何，让我们处理这样的："yyyy-MM-dd'T'HH:mm:ss.SSS'Z'"。尾随'Z'是有趣的部分。通常这里有时区数据，比如-0700. 所以模式将是...Z，即没有撇号。
The output format is way more simple: "dd-MM-yyyy". Mind the small y-s.
输出格式更简单："dd-MM-yyyy". 注意小y-s。
Here is the example code:
这是示例代码：
DateTimeFormatter inputFormatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'", Locale.ENGLISH);
DateTimeFormatter outputFormatter = DateTimeFormatter.ofPattern("dd-MM-yyy", Locale.ENGLISH);
LocalDate date = LocalDate.parse("2018-04-10T04:00:00.000Z", inputFormatter);
String formattedDate = outputFormatter.format(date);
System.out.println(formattedDate); // prints 10-04-2018
Original answer - with old API SimpleDateFormat
原始答案 - 使用旧 API SimpleDateFormat
SimpleDateFormat inputFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
SimpleDateFormat outputFormat = new SimpleDateFormat("dd-MM-yyyy");
Date date = inputFormat.parse("2018-04-10T04:00:00.000Z");
String formattedDate = outputFormat.format(date);
System.out.println(formattedDate); // prints 10-04-2018
回答by Deb
Using Date pattern yyyy-MM-dd'T'HH:mm:ss.SSS'Z'and Java 8 you could do
使用日期模式yyyy-MM-dd'T'HH:mm:ss.SSS'Z'和 Java 8 你可以做
String string = "2018-04-10T04:00:00.000Z";
DateTimeFormatter formatter = DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'", Locale.ENGLISH);
LocalDate date = LocalDate.parse(string, formatter);
System.out.println(date);
Update: For pre 26 use Joda time
更新：对于 26 岁之前使用 Joda 时间
String string = "2018-04-10T04:00:00.000Z";
DateTimeFormatter formatter = DateTimeFormat.forPattern("yyyy-MM-dd'T'HH:mm:ss.SSS'Z'");
LocalDate date = org.joda.time.LocalDate.parse(string, formatter);
In app/build.gradle file, add like this-
在 app/build.gradle 文件中，像这样添加-
dependencies {
compile 'joda-time:joda-time:2.9.4'
}
