asp.net-mvc 如何从 ASP.NET MVC 3 控制器返回 200 HTTP 状态代码
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How to return a 200 HTTP Status Code from ASP.NET MVC 3 controller
提问by Paul Brown
I am writing an application that is accepting POST data from a third party service.
我正在编写一个接受来自第三方服务的 POST 数据的应用程序。
When this data is POSTed I must return a 200 HTTP Status Code.
发布此数据时，我必须返回 200 HTTP 状态代码。
How can I do this from my controller?
我怎样才能从我的控制器做到这一点？
回答by Brian Behm
In your controller you'd return an HttpStatusCodeResult like this...
在你的控制器中，你会像这样返回一个 HttpStatusCodeResult ......
[HttpPost]
public ActionResult SomeMethod(...your method parameters go here...)
{
// todo: put your processing code here
//If not using MVC5
return new HttpStatusCodeResult(200);
//If using MVC5
return new HttpStatusCodeResult(HttpStatusCode.OK); // OK = 200
}
回答by Kevin Stricker
200 is just the normal HTTP header for a successful request. If that's allyou need, just have the controller return new EmptyResult();
200 只是成功请求的正常 HTTP 标头。如果这一切你所需要的，只是有控制器return new EmptyResult();
回答by Hyman
You can simply set the status code of the response to 200 like the following
您可以简单地将响应的状态代码设置为 200，如下所示
public ActionResult SomeMethod(parameters...)
{
//others code here
...
Response.StatusCode = 200;
return YourObject;
}
回答by Brian Ogden
[HttpPost]
public JsonResult ContactAdd(ContactViewModel contactViewModel)
{
if (ModelState.IsValid)
{
var job = new Job { Contact = new Contact() };
Mapper.Map(contactViewModel, job);
Mapper.Map(contactViewModel, job.Contact);
_db.Jobs.Add(job);
_db.SaveChanges();
//you do not even need this line of code,200 is the default for ASP.NET MVC as long as no exceptions were thrown
//Response.StatusCode = (int)HttpStatusCode.OK;
return Json(new { jobId = job.JobId });
}
else
{
Response.StatusCode = (int)HttpStatusCode.BadRequest;
return Json(new { jobId = -1 });
}
}
回答by user1477388
The way to do this in .NET Core is (at the time of writing) as follows:
在 .NET Core 中执行此操作的方法（在撰写本文时）如下：
public async Task<IActionResult> YourAction(YourModel model)
{
if (ModelState.IsValid)
{
return StatusCode(200);
}
return StatusCode(400);
}
The StatusCodemethod returns a type of StatusCodeResultwhich implements IActionResultand can thus be used as a return type of your action.
所述的StatusCode方法返回的类型StatusCodeResult它实现IActionResult并且因此可以用作您的动作的返回类型。
As a refactor, you could improve readability by using a cast of the HTTP status codes enum like:
作为重构，您可以通过使用 HTTP 状态代码枚举的强制转换来提高可读性，例如：
return StatusCode((int)HttpStatusCode.OK);
Furthermore, you could also use some of the built in result types. For example:
此外，您还可以使用一些内置的结果类型。例如：
return Ok(); // returns a 200
return BadRequest(ModelState); // returns a 400 with the ModelState as JSON
Ref. StatusCodeResult - https://docs.microsoft.com/en-us/dotnet/api/microsoft.aspnetcore.mvc.statuscoderesult?view=aspnetcore-2.1
参考 StatusCodeResult - https://docs.microsoft.com/en-us/dotnet/api/microsoft.aspnetcore.mvc.statuscoderesult?view=aspnetcore-2.1
