如何在 bash 脚本中使用包含带空格的文件名的变量？
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How do I use a variable containing a filename with spaces in a bash script?
提问by nick
I have a simple bash script running on OS X that removes specific files and directories and copies new ones in their place. One Mac .app directory contains a space, and when I run the script there is a "No such file or directory" error.
我有一个在 OS X 上运行的简单 bash 脚本，它删除特定的文件和目录并将新的文件和目录复制到它们的位置。一个 Mac .app 目录包含一个空格，当我运行脚本时出现“没有这样的文件或目录”错误。
Here is the relevant code. A good amount has been cut out, so simply hard coding these differently isn't possible (the variables must be broken up as they are):
这是相关的代码。大量已被删减，因此不可能简单地对这些进行硬编码（变量必须按原样分解）：
CP="cp -Rf"
INSTALL_DIR="/Applications/"
APP="The App.app"
NEWAPP="$HOME/Downloads/The App.app"
$CP "$NEWAPP " "$INSTALL_DIR$NEWAPP"
I've tried escaping The\ App.appwith no luck, as well as trying single quoting, double quoting, and double escaping, but nothing has worked. I imagine there is a simple way to do this.
我尝试过The\ App.app没有运气的转义，以及尝试单引号、双引号和双转义，但没有任何效果。我想有一种简单的方法可以做到这一点。
Thanks for your help.
谢谢你的帮助。
回答by Karoly Horvath
You have an extra space there, it's simply
你有一个额外的空间，它只是
"$NEWAPP"
“$NEWAPP”
回答by emergence
enclose the whole final line in quotes:
用引号将整个最后一行括起来：
"$CP $NEWAPP $INSTALL_DIR$NEWAPP"
it's unnecessary to keep opening and closing the quotes here, and the $CP must be contained in quotes as CP has a space in it.
没有必要在这里继续打开和关闭引号，并且 $CP 必须包含在引号中，因为 CP 中有一个空格。
