C语言 中止 C 中的陷阱 6 错误
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Abort trap 6 error in C
提问by user1753491
I have this code:
我有这个代码：
void drawInitialNim(int num1, int num2, int num3)
{
int board[2][50]; //make an array with 3 columns
int i; // i, j, k are loop counters
int j;
int k;
for(i=0;i<num1+1;i++) //fill the array with rocks, or 'O'
board[0][i] = 'O'; //for example, if num1 is 5, fill the first row with 5 rocks
for (i=0; i<num2+1; i++)
board[1][i] = 'O';
for (i=0; i<num3+1; i++)
board[2][i] = 'O';
for (j=0; j<2;j++) { //print the array
for (k=0; k<50;k++) {
printf("%d",board[j][k]);
}
}
return;
}
int main()
{
int numRock1,numRock2,numRock3;
numRock1 = 0;
numRock2 = 0;
numRock3 = 0;
printf("Welcome to Nim!\n");
printf("Enter the number of rocks in each row: ");
scanf("%d %d %d", &numRock1, &numRock2, &numRock3);
drawInitialNim(numRock1, numRock2, numRock3); //call the function
return 0;
}
When I compile this with gcc, it is fine. When I run the file, I get the abort trap 6 error after entering the values.
当我用 gcc 编译它时，它很好。当我运行该文件时，我在输入值后收到 abort trap 6 错误。
I have looked at other posts about this error, and they don't help me.
我已经查看了有关此错误的其他帖子，但它们对我没有帮助。
采纳答案by BLUEPIXY
Try this:
尝试这个：
void drawInitialNim(int num1, int num2, int num3){
int board[3][50] = {0}; // This is a local variable. It is not possible to use it after returning from this function.
int i, j, k;
for(i=0; i<num1; i++)
board[0][i] = 'O';
for(i=0; i<num2; i++)
board[1][i] = 'O';
for(i=0; i<num3; i++)
board[2][i] = 'O';
for (j=0; j<3;j++) {
for (k=0; k<50; k++) {
if(board[j][k] != 0)
printf("%c", board[j][k]);
}
printf("\n");
}
}
回答by ryyker
You are writing to memory you do not own:
您正在写入不属于您的内存：
int board[2][50]; //make an array with 3 columns (wrong)
//(actually makes an array with only two 'columns')
...
for (i=0; i<num3+1; i++)
board[2][i] = 'O';
^
Change this line:
改变这一行：
int board[2][50]; //array with 2 columns (legal indices [0-1][0-49])
^
To:
到：
int board[3][50]; //array with 3 columns (legal indices [0-2][0-49])
^
When creating an array, the value used to initialize: [3]indicates array size.
However, when accessing existing array elements, index values are zero based.
创建数组时，用于初始化的值：[3]表示数组大小。
但是，在访问现有数组元素时，索引值是从零开始的。
For an array created: int board[3][50];
Legal indices are board[0][0]...board[2][49]
对于创建的数组： int board[3][50];
合法索引为 board[0][0]...board[2][49]
EDITTo address bad output comment and initialization comment
编辑以解决错误的输出注释和初始化注释
add an additional "\n" for formatting output:
添加额外的 "\n" 用于格式化输出：
Change:
改变：
...
for (k=0; k<50;k++) {
printf("%d",board[j][k]);
}
}
...
To:
到：
...
for (k=0; k<50;k++) {
printf("%d",board[j][k]);
}
printf("\n");//at the end of every row, print a new line
}
...
Initializeboard variable:
初始化板变量：
int board[3][50] = {0};//initialize all elements to zero
