jQuery 获取提交表单的操作
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get action of submitted form
提问by Elie
I have the following code which is triggered every time a user submits a form on my site.
我有以下代码，每次用户在我的网站上提交表单时都会触发该代码。
I want to modify it slightly, so that it checks the action of the submission, and based on the presence of a particular keyword, runs some code.
我想稍微修改它，以便它检查提交的操作，并根据特定关键字的存在，运行一些代码。
My code is as follows:
我的代码如下：
$("form").submit(function() {
//do some generic stuff
var formAction = ""; //get the action of the submitted form
if (formAction.indexOf('keyword') !== -1) {
//do some specific stuff for these forms
}
});
How do I get the actionof the formwhich triggered this call?
我如何获得action的form，其触发这个电话？
回答by Adriano Carneiro
$("form").submit(function() {
//some stuff...
//get form action:
var formAction = $(this).attr("action");
//some other stuff...
});
回答by Luca C.
if you need Javascript without jQuery:
如果您需要没有 jQuery 的 Javascript：
var action=document.getElementById('formId').action
with jQuery:
使用 jQuery：
var action=$('#formId').attr('action');
回答by Mohammad Adil
You can get action attr this way -
您可以通过这种方式获得动作属性 -
var formAction = $(this).attr("action");
回答by Rusty
In JavaScript, you can use getAttribute method:
在 JavaScript 中，您可以使用 getAttribute 方法：
var form = document.getElementById('register_form');
var action = form.getAttribute("action")
Note:form.getAttribute("action") is safer than using form.action. Because if you have an input field named "action" within a form, then the browser can return that particular node instead of returning action URL of the form.
注意：form.getAttribute("action") 比使用 form.action 更安全。因为如果表单中有一个名为“action”的输入字段，那么浏览器可以返回该特定节点而不是返回表单的操作 URL。
回答by Roko C. Buljan
In "vanilla"JS you have the Element.getAttribute()
Or (if needed) you could use the this.action. See below the slight difference
在“vanilla”JS 中，你有Element.getAttribute()
Or（如果需要）你可以使用this.action. 看下面的细微差别
document.querySelector("form").addEventListener("submit", function(e) {
e.preventDefault(); // Prevents form from submitting
console.log( this.getAttribute("action") ); // "test.php"
console.log( this.action ); // <address>/test.php
// this.submit(); // Submit afterwards or use AJAX to construct your request
});<form action="test.php">
<input type="submit">
</form>