Javascript 向除发送者以外的所有客户端发送响应

Send response to all clients except sender

提问by switz

To send something to all clients, you use:

要将某些内容发送给所有客户端，请使用：

io.sockets.emit('response', data);

To receive from clients, you use:

要从客户那里接收，您可以使用：

socket.on('cursor', function(data) {
  ...
});

How can I combine the two so that when recieving a message on the server from a client, I send that message to all users except the one sending the message?

如何将两者结合起来，以便在服务器上从客户端接收消息时，将该消息发送给除发送消息的用户之外的所有用户？

socket.on('cursor', function(data) {
  io.sockets.emit('response', data);
});

Do I have to hack it around by sending the client-id with the message and then checking on the client-side or is there an easier way?

我是否必须通过发送带有消息的客户端 ID 然后在客户端检查来破解它，还是有更简单的方法？

回答by LearnRPG

Here is my list (updated for 1.0):

这是我的列表（更新为 1.0）：

// sending to sender-client only
socket.emit('message', "this is a test");

// sending to all clients, include sender
io.emit('message', "this is a test");

// sending to all clients except sender
socket.broadcast.emit('message', "this is a test");

// sending to all clients in 'game' room(channel) except sender
socket.broadcast.to('game').emit('message', 'nice game');

// sending to all clients in 'game' room(channel), include sender
io.in('game').emit('message', 'cool game');

// sending to sender client, only if they are in 'game' room(channel)
socket.to('game').emit('message', 'enjoy the game');

// sending to all clients in namespace 'myNamespace', include sender
io.of('myNamespace').emit('message', 'gg');

// sending to individual socketid
socket.broadcast.to(socketid).emit('message', 'for your eyes only');

// list socketid
for (var socketid in io.sockets.sockets) {}
 OR
Object.keys(io.sockets.sockets).forEach((socketid) => {});

回答by soyuka

From the @LearnRPG answer but with 1.0:

来自@LearnRPG 的答案，但使用 1.0：

 // send to current request socket client
 socket.emit('message', "this is a test");

 // sending to all clients, include sender
 io.sockets.emit('message', "this is a test"); //still works
 //or
 io.emit('message', 'this is a test');

 // sending to all clients except sender
 socket.broadcast.emit('message', "this is a test");

 // sending to all clients in 'game' room(channel) except sender
 socket.broadcast.to('game').emit('message', 'nice game');

 // sending to all clients in 'game' room(channel), include sender
 // docs says "simply use to or in when broadcasting or emitting"
 io.in('game').emit('message', 'cool game');

 // sending to individual socketid, socketid is like a room
 socket.broadcast.to(socketid).emit('message', 'for your eyes only');

To answer @Crashalot comment, socketidcomes from:

回答@Crashalot 评论，socketid来自：

var io = require('socket.io')(server);
io.on('connection', function(socket) { console.log(socket.id); })

回答by Vadorequest

Here is a more complete answer about what has changed from 0.9.x to 1.x.

这是关于从 0.9.x 到 1.x 的变化的更完整的答案。

 // send to current request socket client
 socket.emit('message', "this is a test");// Hasn't changed

 // sending to all clients, include sender
 io.sockets.emit('message', "this is a test"); // Old way, still compatible
 io.emit('message', 'this is a test');// New way, works only in 1.x

 // sending to all clients except sender
 socket.broadcast.emit('message', "this is a test");// Hasn't changed

 // sending to all clients in 'game' room(channel) except sender
 socket.broadcast.to('game').emit('message', 'nice game');// Hasn't changed

 // sending to all clients in 'game' room(channel), include sender
 io.sockets.in('game').emit('message', 'cool game');// Old way, DOES NOT WORK ANYMORE
 io.in('game').emit('message', 'cool game');// New way
 io.to('game').emit('message', 'cool game');// New way, "in" or "to" are the exact same: "And then simply use to or in (they are the same) when broadcasting or emitting:" from http://socket.io/docs/rooms-and-namespaces/

 // sending to individual socketid, socketid is like a room
 io.sockets.socket(socketid).emit('message', 'for your eyes only');// Old way, DOES NOT WORK ANYMORE
 socket.broadcast.to(socketid).emit('message', 'for your eyes only');// New way

I wanted to edit the post of @soyuka but my edit was rejected by peer-review.

我想编辑@soyuka 的帖子，但我的编辑被同行评审拒绝了。

回答by Khaled Jouda

broadcast.emit sends the msg to all other clients (except for the sender)

broadcast.emit 将 msg 发送到所有其他客户端（发送者除外）

socket.on('cursor', function(data) {
  socket.broadcast.emit('msg', data);
});

回答by Prasanna Brabourame

Emit cheatsheet

发出备忘单

io.on('connect', onConnect);

function onConnect(socket){

  // sending to the client
  socket.emit('hello', 'can you hear me?', 1, 2, 'abc');

  // sending to all clients except sender
  socket.broadcast.emit('broadcast', 'hello friends!');

  // sending to all clients in 'game' room except sender
  socket.to('game').emit('nice game', "let's play a game");

  // sending to all clients in 'game1' and/or in 'game2' room, except sender
  socket.to('game1').to('game2').emit('nice game', "let's play a game (too)");

  // sending to all clients in 'game' room, including sender
  io.in('game').emit('big-announcement', 'the game will start soon');

  // sending to all clients in namespace 'myNamespace', including sender
  io.of('myNamespace').emit('bigger-announcement', 'the tournament will start soon');

  // sending to individual socketid (private message)
  socket.to(<socketid>).emit('hey', 'I just met you');

  // sending with acknowledgement
  socket.emit('question', 'do you think so?', function (answer) {});

  // sending without compression
  socket.compress(false).emit('uncompressed', "that's rough");

  // sending a message that might be dropped if the client is not ready to receive messages
  socket.volatile.emit('maybe', 'do you really need it?');

  // sending to all clients on this node (when using multiple nodes)
  io.local.emit('hi', 'my lovely babies');

};

回答by runspired

For namespaces within rooms looping the list of clients in a room (similar to Nav's answer) is one of only two approaches I've found that will work. The other is to use exclude. E.G.

对于房间内的命名空间，循环房间中的客户端列表（类似于 Nav 的答案）是我发现的仅有的两种可行方法之一。另一种是使用排除。例如

socket.on('message',function(data) {
    io.of( 'namespace' ).in( data.roomID ).except( socket.id ).emit('message',data);
}

回答by Kent Aguilar

Updated the list for further documentation.

更新了列表以获取更多文档。

socket.emit('message', "this is a test"); //sending to sender-client only
socket.broadcast.emit('message', "this is a test"); //sending to all clients except sender
socket.broadcast.to('game').emit('message', 'nice game'); //sending to all clients in 'game' room(channel) except sender
socket.to('game').emit('message', 'enjoy the game'); //sending to sender client, only if they are in 'game' room(channel)
socket.broadcast.to(socketid).emit('message', 'for your eyes only'); //sending to individual socketid
io.emit('message', "this is a test"); //sending to all clients, include sender
io.in('game').emit('message', 'cool game'); //sending to all clients in 'game' room(channel), include sender
io.of('myNamespace').emit('message', 'gg'); //sending to all clients in namespace 'myNamespace', include sender
socket.emit(); //send to all connected clients
socket.broadcast.emit(); //send to all connected clients except the one that sent the message
socket.on(); //event listener, can be called on client to execute on server
io.sockets.socket(); //for emiting to specific clients
io.sockets.emit(); //send to all connected clients (same as socket.emit)
io.sockets.on() ; //initial connection from a client.

Hope this helps.

希望这可以帮助。

回答by Kim Thien Dung

Other cases

其他情况

io.of('/chat').on('connection', function (socket) {
    //sending to all clients in 'room' and you
    io.of('/chat').in('room').emit('message', "data");
};

回答by reabow

I am using namespaces and rooms - I found

我正在使用命名空间和房间 - 我发现

socket.broadcast.to('room1').emit('event', 'hi');

to work where

去哪里工作

namespace.broadcast.to('room1').emit('event', 'hi');

did not

没有

(should anyone else face that problem)

（如果其他人遇到这个问题）

回答by Abi

use this coding

使用这种编码

io.sockets.on('connection', function (socket) {

    socket.on('mousemove', function (data) {

        socket.broadcast.emit('moving', data);
    });

this socket.broadcast.emit() will emit everthing in the function except to the server which is emitting

此 socket.broadcast.emit() 将发出函数中的所有内容，除了正在发出的服务器