Android 如何检查定位服务是否启用？
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How to check if Location Services are enabled?
提问by Meroelyth
I'm developing an app on Android OS. I don't know how to check if Location Services are enabled or not.
我正在 Android 操作系统上开发应用程序。我不知道如何检查是否启用了定位服务。
I need a method that returns "true" if they are enabled and "false" if not (so in the last case I can show a dialog to enable them).
我需要一个方法，如果启用它们返回“真”，否则返回“假”（所以在最后一种情况下，我可以显示一个对话框来启用它们）。
回答by Shankar Agarwal
You can use the below code to check whether gps provider and network providers are enabled or not.
您可以使用以下代码来检查是否启用了 GPS 提供商和网络提供商。
LocationManager lm = (LocationManager)context.getSystemService(Context.LOCATION_SERVICE);
boolean gps_enabled = false;
boolean network_enabled = false;
try {
gps_enabled = lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
} catch(Exception ex) {}
try {
network_enabled = lm.isProviderEnabled(LocationManager.NETWORK_PROVIDER);
} catch(Exception ex) {}
if(!gps_enabled && !network_enabled) {
// notify user
new AlertDialog.Builder(context)
.setMessage(R.string.gps_network_not_enabled)
.setPositiveButton(R.string.open_location_settings, new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface paramDialogInterface, int paramInt) {
context.startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
}
}
.setNegativeButton(R.string.Cancel,null)
.show();
}
And in the manifest file, you will need to add the following permissions
并且在清单文件中，您需要添加以下权限
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>
<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>
回答by Slava Fir
I use this code for checking:
我使用此代码进行检查：
public static boolean isLocationEnabled(Context context) {
int locationMode = 0;
String locationProviders;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
try {
locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);
} catch (SettingNotFoundException e) {
e.printStackTrace();
return false;
}
return locationMode != Settings.Secure.LOCATION_MODE_OFF;
}else{
locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
return !TextUtils.isEmpty(locationProviders);
}
}
回答by Mayank Sharma
As now in 2019
就像现在在 2019 年
Latest , Best and shortest way is
最新，最好和最短的方法是
public static Boolean isLocationEnabled(Context context)
{
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.P) {
// This is new method provided in API 28
LocationManager lm = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
return lm.isLocationEnabled();
} else {
// This is Deprecated in API 28
int mode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE,
Settings.Secure.LOCATION_MODE_OFF);
return (mode != Settings.Secure.LOCATION_MODE_OFF);
}
}
回答by lenik
You may use this code to direct users to Settings, where they can enable GPS:
您可以使用此代码将用户引导至设置，他们可以在其中启用 GPS：
locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
if( !locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) ) {
new AlertDialog.Builder(context)
.setTitle(R.string.gps_not_found_title) // GPS not found
.setMessage(R.string.gps_not_found_message) // Want to enable?
.setPositiveButton(R.string.yes, new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialogInterface, int i) {
owner.startActivity(new Intent(android.provider.Settings.ACTION_LOCATION_SOURCE_SETTINGS));
}
})
.setNegativeButton(R.string.no, null)
.show();
}
回答by Sunny
Migrate to Android X and use
迁移到 Android X 并使用
implementation 'androidx.appcompat:appcompat:1.1.0'
and use LocationManagerCompat
并使用 LocationManagerCompat
In java
在 Java 中
private boolean isLocationEnabled(Context context) {
LocationManager locationManager = (LocationManager) context.getSystemService(Context.LOCATION_SERVICE);
return LocationManagerCompat.isLocationEnabled(locationManager);
}
In Kotlin
在科特林
private fun isLocationEnabled(context: Context): Boolean {
val locationManager = context.getSystemService(Context.LOCATION_SERVICE) as LocationManager
return LocationManagerCompat.isLocationEnabled(locationManager)
}
回答by ZaBlanc
Working off the answer above, in API 23 you need to add "dangerous" permissions checks as well as checking the system's itself:
解决上面的答案，在 API 23 中，您需要添加“危险”权限检查以及检查系统本身：
public static boolean isLocationServicesAvailable(Context context) {
int locationMode = 0;
String locationProviders;
boolean isAvailable = false;
if (Build.VERSION.SDK_INT >= Build.VERSION_CODES.KITKAT){
try {
locationMode = Settings.Secure.getInt(context.getContentResolver(), Settings.Secure.LOCATION_MODE);
} catch (Settings.SettingNotFoundException e) {
e.printStackTrace();
}
isAvailable = (locationMode != Settings.Secure.LOCATION_MODE_OFF);
} else {
locationProviders = Settings.Secure.getString(context.getContentResolver(), Settings.Secure.LOCATION_PROVIDERS_ALLOWED);
isAvailable = !TextUtils.isEmpty(locationProviders);
}
boolean coarsePermissionCheck = (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_COARSE_LOCATION) == PackageManager.PERMISSION_GRANTED);
boolean finePermissionCheck = (ContextCompat.checkSelfPermission(context, Manifest.permission.ACCESS_FINE_LOCATION) == PackageManager.PERMISSION_GRANTED);
return isAvailable && (coarsePermissionCheck || finePermissionCheck);
}
回答by Arun kumar
Yes you can check below is the code:
是的，您可以查看以下代码：
public boolean isGPSEnabled(Context mContext)
{
LocationManager lm = (LocationManager)
mContext.getSystemService(Context.LOCATION_SERVICE);
return lm.isProviderEnabled(LocationManager.GPS_PROVIDER);
}
with the permission in the manifest file:
具有清单文件中的权限：
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
回答by Risadinha
If no provider is enabled, "passive" is the best provider returned. See https://stackoverflow.com/a/4519414/621690
如果未启用提供程序，则“被动”是返回的最佳提供程序。见https://stackoverflow.com/a/4519414/621690
public boolean isLocationServiceEnabled() {
LocationManager lm = (LocationManager)
this.getSystemService(Context.LOCATION_SERVICE);
String provider = lm.getBestProvider(new Criteria(), true);
return (StringUtils.isNotBlank(provider) &&
!LocationManager.PASSIVE_PROVIDER.equals(provider));
}
回答by tsemann
This if clause easily checks if location services are available in my opinion:
在我看来，这个 if 子句很容易检查定位服务是否可用：
LocationManager locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
if(!locationManager.isProviderEnabled(LocationManager.GPS_PROVIDER) && !locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)) {
//All location services are disabled
}
回答by P. Dm
I use such way for NETWORK_PROVIDERbut you can add and for GPS.
我将这种方式用于NETWORK_PROVIDER但您可以添加 和 用于GPS。
LocationManager locationManager;
In onCreateI put
在onCreate我把
isLocationEnabled();
if(!isLocationEnabled()) {
AlertDialog.Builder builder = new AlertDialog.Builder(MainActivity.this);
builder.setTitle(R.string.network_not_enabled)
.setMessage(R.string.open_location_settings)
.setPositiveButton(R.string.yes,
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
startActivity(new Intent(Settings.ACTION_LOCATION_SOURCE_SETTINGS));
}
})
.setNegativeButton(R.string.cancel,
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
dialog.cancel();
}
});
AlertDialog alert = builder.create();
alert.show();
}
And method of checking
和检查方法
protected boolean isLocationEnabled(){
String le = Context.LOCATION_SERVICE;
locationManager = (LocationManager) getSystemService(le);
if(!locationManager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)){
return false;
} else {
return true;
}
}
