laravel 拉拉维尔 | 在通知中传递变量
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Laravel | Passing variable in Notify
提问by Laynom Graphic
I want to send a mail to Notify, it works but when I try to put the variables, It returns that they are undefined. I don't understand how to pass a variable to Notify, I tried to do ->withResult($result)but it didn't work out.
Here is the controller:
我想向 Notify 发送邮件，它可以工作，但是当我尝试放置变量时，它返回它们未定义。我不明白如何将变量传递给 Notify，我尝试这样做，->withResult($result)但没有成功。这是控制器：
$result = Review::where('user_hash', '=', $data['lname_c'])->where('email', $data['email_c'])->orderBy('created_at', 'desc')->first();
$result->notify(new SendReview());
And my SendReview.php notifications:
还有我的 SendReview.php 通知：
public function toMail($notifiable)
{
return $result['invitation_id']; // test to check if variable is passed
return (new MailMessage)
->line('Test.')
->action('Nani', url($url))
->line('Thank you');
}
There is user_hash and invitation_id in my Review table, I want to pass them to the notify. When I do return $result['invitation_id'];it works. Hope I am understandable, I checked for duplicate questions and couldn't find one.
我的Review表中有user_hash和invitation_id，我想将它们传递给notify。当我这样做return $result['invitation_id'];时。希望我可以理解，我检查了重复的问题，但找不到。
回答by Paul Santos
This is how they do it in docs.
这就是他们在文档中的做法。
$arr = [ 'foo' => "bar" ];
$result->notify(new SendReview($arr));
And in your SendReview.php
而在你 SendReview.php
...
protected $arr;
public function __construct(array $arr) {
$this->arr = $arr;
}
public function toMail($notifiable) {
// Access your array in here
dd($this->arr);
}
回答by Amit Gupta
You must use $notifiablevariable in your Notificationclass.
您必须$notifiable在Notification类中使用变量。
It is an instance of the class to which the notification is being sent. So here your review object is passed as $notifiablevariable.
它是向其发送通知的类的实例。所以在这里你的评论对象作为$notifiable变量传递。
You can try to log it as logger($notifiable)in toMail()method and check its properties.
您可以尝试将其记录作为logger($notifiable)在toMail()方法和检查其属性。
