如何格式化 Pandas timedelta 对象？
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How Do I Format a pandas timedelta object?
提问by psychemedia
I am using pandastimedeltaobjects to keep track of split times in a sports related data set using the following sort of construction:
我正在使用Pandastimedelta对象来跟踪体育相关数据集中的分割时间，使用以下类型的构造：
import pandas as pd
pd.to_timedelta("-0:0:1.0")
This natively reports as:
这本机报告为：
-1 days +23:59:59
-1 days +23:59:59
I can get the raw seconds count using pd.to_timedelta("-0:0:1.0").total_seconds()but that is unwieldy where the negative amount is in minutes or hours:
我可以使用原始秒数计算，pd.to_timedelta("-0:0:1.0").total_seconds()但如果负数以分钟或小时为单位，那就很笨拙了：
For the expression:
对于表达式：
pd.to_timedelta("-1:2:3.0")
how can I get the report formatted as"-1:2:3.0, or -1 hour, 2 minutes, 3 seconds, from the timedeltaobject, rather than in the form -3723.0000000000005(with a float error) or -1 days +22:57:57?
如何从对象中获取格式为"-1:2:3.0, 或的报告，而不是格式（带有浮点错误）或？-1 hour, 2 minutes, 3 secondstimedelta-3723.0000000000005-1 days +22:57:57
采纳答案by psychemedia
See the function strfdelta(tdelta, fmt)provided as an answer to a related question: https://stackoverflow.com/a/8907269/454773
请参阅strfdelta(tdelta, fmt)作为相关问题答案提供的函数：https: //stackoverflow.com/a/8907269/454773
回答by MaxU
Is that what you want?
那是你要的吗？
In [223]: df
Out[223]:
delta
0 -1 days +23:59:59
1 -1 days +22:57:57
2 00:00:11
In [224]: df.delta.abs().dt.components
Out[224]:
days hours minutes seconds milliseconds microseconds nanoseconds
0 0 0 0 1 0 0 0
1 0 1 2 3 0 0 0
2 0 0 0 11 0 0 0
