vb.net VB.NET中List.Find的使用

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时间:2020-09-09 16:39:23  来源:igfitidea点击:

Use of List.Find in VB.NET

vb.netlistfind

提问by Syed Md. Kamruzzaman

I have two columns. One column contains string values and another column contains decimal values. I want to select the decimal value by selecting the string value.

我有两列。一列包含字符串值,另一列包含十进制值。我想通过选择字符串值来选择十进制值。

string          decimal
Jewel           10
Hasan           20

How do I select Jewel so it will return 10?

如何选择 Jewel 使其返回 10?

回答by Andrey Gordeev

Try this:

尝试这个:

Dim selectedValues As List(Of InvoiceSOA)
selectedValues = DisputeList.FindAll(Function(p) p.ColumnName = "Jewel")

Or, if you need the first occurence of "Jewel" use this:

或者,如果您需要第一次出现“Jewel”,请使用以下命令:

Dim selectedValue As InvoiceSOA
selectedValue = DisputeList.Find(Function(p) p.ColumnName = "Jewel")

回答by Badz

Dim selectedValue As InvoiceSOA = DisputeList.Find(Function(p) 
        if p.ColumnName = "Jewel" then
            return true
        end if
    end function)

回答by Venkat

The Enum functionality is the right way to use for this question.

Enum 功能是解决这个问题的正确方法。

Example:

例子:

Public Enum Ornaments
    Neclace = 10
    Bangle = 20
    TieClip = 30
End Enum

How to use this Enum

如何使用这个枚举

Dim SelectedOrnament As Ornaments = Ornaments.Bangle

Select Case SelectedOrnament

    Case Ornaments.Neclace
        MsgBox("Your ornament is: " & Ornaments.Neclace)

    Case Ornaments.Bangle
        MsgBox("Your ornament is: " & Ornaments.Bangle)

    Case Ornaments.TieClip
        MsgBox("Your ornament is: " & Ornaments.TieClip)

    Case Else
        MsgBox("I could not find your ornament. Sorry")

End Select