Javascript TypeError: (intermediate value)(intermediate value).success 不是函数（角度）
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TypeError: (intermediate value)(intermediate value).success is not a function (angular)
提问by kkdeveloper7
I have difficulties understanding this error... I dont quite understand why its not a function....
我很难理解这个错误......我不太明白为什么它不是一个函数......
angular.module('mkApp').factory('mkService', function ($http, $log) {
function getLookUp(successcb) {
$http = ({
method: 'GET',
url: 'api/Entries/'
}).success(function (data, status, header, config) {
successcb(data);
}).
error(function (data, status, header, config) {
$log, warn(data, status, header, config);
});
};
return {
lookUp: getLookUp
}
});
angular.module('mkApp').controller('mkControler', function ($scope, mkService) {
mkService.lookUp(function (data) {
$scope.ddl = data;
console.log(ddl);
});
});
And here is my HTML
这是我的 HTML
<div ng-app="mkApp">
<div ng-controller="mkControler">
<table>
<tr>
<td> First Name</td>
<td> Last Name</td>
</tr>
<tr>
<td><input type="text" /></td>
<td><input type="text" /></td>
</tr>
<tr>
<td>
<select></select>
</td>
</tr>
</table>
</div>
</div>
My idea is to use data to populate drop down. It does bring me XML back. Any help please i've been looking everywhere now. Thank you.
我的想法是使用数据来填充下拉列表。它确实让我回到了 XML。任何帮助，我一直在到处寻找。谢谢你。
回答by Pankaj Parkar
Your $httpcall code should be $http({instead of $http = ({and also $log, warnshould be $log.warn
您的$http通话代码应该是$http({不是$http = ({也$log, warn应该$log.warn
Code
代码
$http({
method: 'GET',
url: 'api/Entries/'
}).success(function (data, status, header, config) {
successcb(data);
}).
error(function (data, status, header, config) {
$log.warn(data, status, header, config);
});
