typescript 打字稿：如何导出变量
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Typescript: How to export a variable
提问by CrazySynthax
I want to open 'file1.ts' and write:
我想打开'file1.ts'并写：
export var arr = [1,2,3];
and open another file, let's say 'file2.ts' and access directly to 'arr' in file1.ts:
并打开另一个文件，假设'file2.ts'并直接访问file1.ts中的'arr'：
I do it by:
我这样做：
import {arr} from './file1';
However, when I want to access 'arr', I can't just write 'arr', but I have to write 'arr.arr'. The first one is for the module name. How do I access directly an exported variable name?
但是，当我想访问'arr'时，我不能只写'arr'，而是必须写'arr.arr'。第一个是模块名称。如何直接访问导出的变量名称？
回答by Kieran
There are two different types of export, namedand default.
有两种不同类型的导出，named和default。
You can have multiple named exports per module but only one default export.
每个模块可以有多个命名导出，但只能有一个默认导出。
For a named export you can try something like:
对于命名导出，您可以尝试以下操作：
// ./file1.ts
const arr = [1,2,3];
export { arr };
Then to import you could use the original statement:
然后导入您可以使用原始语句：
// ./file2
import { arr } from "./file1";
console.log(arr.length);
This will get around the need for arr.arryou mentioned.
这将解决arr.arr您提到的需求。
回答by Mikael Gidmark
If you do:
如果你这样做：
var arr = [1,2,3];
export default arr;
...
...
import arr from './file1';
Then it should work
那么它应该工作
