java 自定义 JavaFX 对话框
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Custom JavaFX Dialog
提问by Dejwi
I want to create a custom JavaFX dialog. So far I've create something like that:
我想创建一个自定义的 JavaFX 对话框。到目前为止,我已经创建了类似的东西:
public class LoginDialog extends Dialog {
public LoginDialog(Data data) {
try {
FXMLLoader loader = new FXMLLoader(getClass().getResource("fxml/LoginDialog.fxml"));
Parent root = loader.load();
LoginDialogController controller = loader.<LoginDialogController>getController();
controller.setModel(new LoginModel(data));
getDialogPane().setContent(root);
} catch (IOException e) {
e.printStackTrace();
}
}
}
But - at first I'm not convinced that this is the right way to do this.
但是 - 起初我不相信这是做到这一点的正确方法。
Secondly - I wish to use a Button declared in LoginDialog.fxml file to close this LoginDialog, after showAndWait() call. Is it possible? How can I set the return value?
其次 - 在 showAndWait() 调用之后,我希望使用在 LoginDialog.fxml 文件中声明的 Button 来关闭这个 LoginDialog。是否可以?如何设置返回值?
回答by James_D
Close the window from the controller:
从控制器关闭窗口:
public class LoginDialogController {
@FXML
private Button button ;
@FXML
private void handleButtonPress() {
button.getScene().getWindow().hide();
}
// ...
}
(and in the FXML you need something like <Button fx:id="button" onAction="#handleButtonPress" ... />
)
(在 FXML 中,您需要类似的东西<Button fx:id="button" onAction="#handleButtonPress" ... />
)
To return a value, specify the type for the dialog and set the result converter:
要返回一个值,请指定对话框的类型并设置结果转换器:
public class LoginDialog extends Dialog<SomeDataType> {
public LoginDialog(Data data) {
try {
FXMLLoader loader = new FXMLLoader(getClass().getResource("fxml/LoginDialog.fxml"));
Parent root = loader.load();
LoginDialogController controller = loader.<LoginDialogController>getController();
controller.setModel(new LoginModel(data));
getDialogPane().setContent(root);
setResultConverter(buttonType -> {
SomeDataType someData = ... ;
return someData ;
});
} catch (IOException e) {
e.printStackTrace();
}
}
}
Obviously you can reference the controller in the result converter, call methods on it, etc, so you can return different values depending on what the user does in the UI.
显然,您可以在结果转换器中引用控制器,对其调用方法等,因此您可以根据用户在 UI 中的操作返回不同的值。
回答by Rahul Singh
You can create a dialog using the following way
您可以使用以下方式创建对话框
public void popup() {
final Stage dialog = new Stage();
dialog.setTitle("Confirmation");
Button yes = new Button("Yes");
Button no = new Button("No");
Label displayLabel = new Label("What do you want to do ?");
displayLabel.setFont(Font.font(null, FontWeight.BOLD, 14));
dialog.initModality(Modality.NONE);
dialog.initOwner((Stage) tableview.getScene().getWindow());
HBox dialogHbox = new HBox(20);
dialogHbox.setAlignment(Pos.CENTER);
VBox dialogVbox1 = new VBox(20);
dialogVbox1.setAlignment(Pos.CENTER_LEFT);
VBox dialogVbox2 = new VBox(20);
dialogVbox2.setAlignment(Pos.CENTER_RIGHT);
dialogHbox.getChildren().add(displayLabel);
dialogVbox1.getChildren().add(yes);
dialogVbox2.getChildren().add(no);
yes.addEventHandler(MouseEvent.MOUSE_CLICKED,
new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent e) {
// inside here you can use the minimize or close the previous stage//
dialog.close();
}
});
no.addEventHandler(MouseEvent.MOUSE_CLICKED,
new EventHandler<MouseEvent>() {
@Override
public void handle(MouseEvent e) {
dialog.close();
}
});
dialogHbox.getChildren().addAll(dialogVbox1, dialogVbox2);
Scene dialogScene = new Scene(dialogHbox, 500, 40);
dialogScene.getStylesheets().add("//style sheet of your choice");
dialog.setScene(dialogScene);
dialog.show();
}
This method is preferable by me as i donot have to create a sepearate controller and i get a pop up
我更喜欢这种方法,因为我不必创建单独的控制器并且我会弹出