Javascript AngularJS 在范围内获取所选项目

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时间:2020-08-23 03:27:02  来源:igfitidea点击:

AngularJS get selected item in scope

javascriptangularjsionic-framework

提问by Alex

I'm developing app with Ionic and AngularJS. Can't figure how to get value of selected option

我正在使用 Ionic 和 AngularJS 开发应用程序。无法弄清楚如何获取所选选项的值

Controller

控制器

.controller('TestCtrl', function($scope, $options) {
    $scope.options = [
        { id: 0, label: '15', value: 15 },
        { id: 1, label: '30', value: 30 },
        { id: 2, label: '60', value: 60 }
    ]

    $scope.countSelector = $scope.options[0];

    $scope.changeCount = function(obj){
        obj = JSON.parse(obj);
        console.log(obj)
        console.log(countSelector)
        $options.set('productCountPerPageValue', obj.value);
        $options.set('productCountPerPage', obj.id);
    };
    ...
})

Template

模板

<ion-list ng-controller="TestCtrl">

    <label class="item item-input item-select">
        <div class="input-label">
            {{countSelector}}
        </div>
        <select ng-model="countSelector" ng-change="changeCount('{{countSelector}}')" ng-options="opt as opt.label for opt in options">
        </select>
    </label>

</ion-list>

console.log(obj)Always return previously selected value

console.log(obj)总是返回先前选择的值

console.log(countSelector)Always return default value (if set) or undefined

console.log(countSelector)总是返回默认值(如果设置)或未定义

采纳答案by Deblaton Jean-Philippe

When you do select ng-model="countSelector", you are binding your select to $scope.countSelector

当您这样做时select ng-model="countSelector",您将选择绑定到$scope.countSelector

So, inside your controller, if you want to have an access to your selected value, you use the following :

因此,在您的控制器中,如果您想访问您选择的值,请使用以下命令:

$scope.countSelector

edit :

编辑 :

according to your requirements, you might want to have directly the value inside $scope.countSelector. To do so, you can adapt your ng-options to the following :

根据您的要求,您可能希望直接拥有 $scope.countSelector 中的值。为此,您可以将 ng-options 调整为以下内容:

ng-options="opt.id as opt.label for opt in options"

回答by DTing

You are passing in the string version of your countSelector to your ng-change function. If you look at the html it looks like this:

您将 countSelector 的字符串版本传递给 ng-change 函数。如果你看一下html,它看起来像这样:

<select ng-model="countSelector" 
                  ng-change="changeCount('{&quot;id&quot;:1,&quot;label&quot;:&quot;30&quot;,&quot;value&quot;:30}')" 
                  ng-options="opt as opt.label for opt in options" class="ng-valid ng-dirty">

You technically can pass the countSelector into your function by not using an expression:

从技术上讲,您可以通过不使用表达式将 countSelector 传递到您的函数中:

<select ng-model="countSelector" ng-change="changeCount(countSelector)" ng-options="opt as opt.label for opt in options">

http://jsfiddle.net/r2zgmgq1/

http://jsfiddle.net/r2zgmgq1/

As @Deblaton Jean-Philippe answer explains, you have access to that via the scope so it's not really needed.

正如@Deblaton Jean-Philippe 的回答所解释的那样,您可以通过范围访问它,因此它并不是真正需要的。