php 从 json 编码中获取值
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php get values from json encode
提问by conmen
I have an url passing parameters use json_encode each values like follow:
我有一个 url 传递参数使用 json_encode 每个值，如下所示：
$json = array
(
'countryId' => $_GET['CountryId'],
'productId' => $_GET['ProductId'],
'status' => $_GET['ProductId'],
'opId' => $_GET['OpId']
);
echo json_encode($json);
It's returned a result as:
它返回的结果如下：
{
"countryId":"84",
"productId":"1",
"status":"0",
"opId":"134"
}
Can I use json_decodeto parse each values for further data processing?
我可以json_decode用来解析每个值以进行进一步的数据处理吗？
Thanks.
谢谢。
回答by Mihai Iorga
json_decode()will return an object or array if second value it's true:
json_decode()如果第二个值为真，将返回一个对象或数组：
$json = '{"countryId":"84","productId":"1","status":"0","opId":"134"}';
$json = json_decode($json, true);
echo $json['countryId'];
echo $json['productId'];
echo $json['status'];
echo $json['opId'];
回答by Vladimir Hraban
json_decode will return the same array that was originally encoded. For instanse, if you
json_decode 将返回与最初编码相同的数组。例如，如果你
$array = json_decode($json, true);
echo $array['countryId'];
OR
或者
$obj= json_decode($json);
echo $obj->countryId;
These both will echo 84. I think json_encode and json_decode function names are self-explanatory...
这些都会回显 84。我认为 json_encode 和 json_decode 函数名称是不言自明的......
