Linux 如何计算整个文件中字符串出现的次数？
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How do I count the number of occurrences of a string in an entire file?
提问by toop
Is there an inbuilt command to do this or has anyone had any luck with a script that does it?
是否有内置命令可以执行此操作，或者是否有人对执行此操作的脚本有任何运气？
I am looking to count the number of times a certain string (not word) appears in a file. This can include multiple occurrences per line so the count should count every occurrence not just count 1 for lines that have the string 2 or more times.
我正在计算某个字符串（不是单词）在文件中出现的次数。这可以包括每行多次出现，因此计数应该对每次出现计数，而不仅仅是对具有 2 次或更多次字符串的行计数 1。
For example, with this sample file:
例如，使用此示例文件：
blah(*)wasp( *)jkdjs(*)kdfks(l*)ffks(dl
flksj(*)gjkd(*
)jfhk(*)fj (*) ks)(*gfjk(*)
If I am looking to count the occurrences of the string (*)I would expect the count to be 6, i.e. 2 from the first line, 1 from the second line and 3 from the third line. Note how the one across lines 2-3 does not count because there is a LF character separating them.
如果我想计算字符串的出现次数，(*)我希望计数为 6，即第一行 2，第二行 1，第三行 3。请注意，第 2-3 行的那个不计算在内，因为它们之间有一个 LF 字符。
Update: great responses so far! Can I ask that the script handle the conversion of (*)to \(*\), etc? That way I could just pass any desired string as an input parameter without worrying about what conversion needs to be done to it so it appears in the correct format.
更新：到目前为止反应很好！我可以要求脚本处理(*)to\(*\)等的转换吗？这样我就可以将任何所需的字符串作为输入参数传递，而不必担心需要对其进行什么转换，以便它以正确的格式显示。
采纳答案by TLP
Using perl's "Eskimo kiss" operator with the -nswitch to print a total at the end. Use \Q...\Eto ignore any meta characters.
使用 perl 的“爱斯基摩吻”操作符和-n开关在最后打印总数。使用\Q...\E忽略任何元字符。
perl -lnwe '$a+=()=/\Q(*)/g; }{ print $a;' file.txt
Script:
脚本：
use strict;
use warnings;
my $count;
my $text = shift;
while (<>) {
$count += () = /\Q$text/g;
}
print "$count\n";
Usage:
用法：
perl script.pl "(*)" file.txt
回答by DavidO
This loops over the lines of the file, and on each line finds all occurrences of the string "(*)". Each time that string is found, $c is incremented. When there are no more lines to loop over, the value of $c is printed.
这会遍历文件的各行，并在每一行中查找所有出现的字符串“(*)”。每次找到该字符串时，$c 都会递增。当没有更多行要循环时，将打印 $c 的值。
perl -ne'$c++ while /\(\*\)/g;END{print"$c\n"}' filename.txt
perl -ne'$c++ while /\(\*\)/g;END{print"$c\n"}' filename.txt
Update:Regarding your comment asking that this be converted into a solution that accepts a regex as an argument, you might do it like this:
更新：关于您的评论要求将其转换为接受正则表达式作为参数的解决方案，您可以这样做：
perl -ne'BEGIN{$re=shift;}$c++ while /\Q$re/g;END{print"$c\n"}' 'regex' filename.txt
perl -ne'BEGIN{$re=shift;}$c++ while /\Q$re/g;END{print"$c\n"}' 'regex' filename.txt
That ought to do the trick. If I felt inclined to skim through perlrunagain I might see a more elegant solution, but this should work.
那应该可以解决问题。如果我想再次浏览perlrun，我可能会看到一个更优雅的解决方案，但这应该可行。
You could also eliminate the explicit inner while loop in favor of an implicit one by providing list context to the regexp:
您还可以通过向正则表达式提供列表上下文来消除显式内部 while 循环，以支持隐式循环：
perl -ne'BEGIN{$re=shift}$c+=()=/\Q$re/g;END{print"$c\n"}' 'regex' filename.txt
perl -ne'BEGIN{$re=shift}$c+=()=/\Q$re/g;END{print"$c\n"}' 'regex' filename.txt
回答by kev
You can use basic tools such as grepand wc:
您可以使用基本工具，例如grep和wc：
grep -o '(\*)' input.txt | wc -l
回答by Jahid
text="(\*)"
grep -o $text file | wc -l
You can make it into a script which accepts arguments like this:
你可以把它变成一个脚本，它接受这样的参数：
script count:
脚本计数：
#!/bin/bash
text=""
file=""
grep -o "$text" "$file" | wc -l
Usage:
用法：
./count "(\*)" file_path
回答by Arijit Panda
You can use basic grepcommand:
您可以使用基本的grep命令：
Example: If you want to find the no of occurrence of "hello" word in a file
示例：如果要查找文件中“hello”单词出现的次数
grep -c "hello" filename
If you want to find the no of occurrence of a pattern then
如果你想找到一个模式出现的次数，那么
grep -c -P "Your Pattern"
Pattern example : hell.w, \d+etc
模式示例：hell.w、\d+等
回答by Abhishek Singh
I have used below command to find particular string count in a file
我使用以下命令在文件中查找特定的字符串数
grep search_String fileName|wc -l
grep search_String 文件名|wc -l
