Java 如何使用任何空格字符作为分隔符拆分字符串
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How to split a string with any whitespace chars as delimiters
提问by mcjabberz
What regex pattern would need I to pass to java.lang.String.split()to split a String into an Array of substrings using all whitespace characters (' ', '\t', '\n', etc.) as delimiters?
什么正则表达式模式需要我传递给 java.lang.String.split()拆分成字符串使用的所有空格字符（子字符串数组' '，'\t'，'\n'，等）作为分隔符？
采纳答案by Henrik Paul
Something in the lines of
某事在
myString.split("\s+");
This groups all white spaces as a delimiter.
这将所有空格分组为分隔符。
So if I have the string:
所以如果我有字符串：
"Hello[space][tab]World"
This should yield the strings "Hello"and "World"and omit the empty space between the [space]and the [tab].
这应该产生字符串"Hello"并"World"省略[space]和之间的空格[tab]。
As VonC pointed out, the backslash should be escaped, because Java would first try to escape the string to a special character, and send thatto be parsed. What you want, is the literal "\s", which means, you need to pass "\\s". It can get a bit confusing.
正如 VonC 所指出的，应该对反斜杠进行转义，因为 Java 会首先尝试将字符串转义为特殊字符，然后将其发送以进行解析。你想要的是文字"\s"，这意味着，你需要通过"\\s". 它可能会有点混乱。
The \\sis equivalent to [ \\t\\n\\x0B\\f\\r].
在\\s相当于[ \\t\\n\\x0B\\f\\r]。
回答by VonC
"\\s+" should do the trick
"\\s+" 应该可以解决问题
回答by glenatron
In most regex dialects there are a set of convenient character summaries you can use for this kind of thing - these are good ones to remember:
在大多数正则表达式方言中，您可以使用一组方便的字符摘要来处理此类事情 - 这些是值得记住的：
\w- Matches any word character.
\w- 匹配任何单词字符。
\W- Matches any nonword character.
\W- 匹配任何非单词字符。
\s- Matches any white-space character.
\s- 匹配任何空白字符。
\S- Matches anything but white-space characters.
\S- 匹配除空白字符以外的任何内容。
\d- Matches any digit.
\d- 匹配任何数字。
\D- Matches anything except digits.
\D- 匹配除数字以外的任何内容。
A search for "Regex Cheatsheets" should reward you with a whole lot of useful summaries.
搜索“Regex Cheatsheets”应该会为您提供大量有用的摘要。
回答by Rishabh
Since it is a regular expression, and i'm assuming u would also not want non-alphanumeric chars like commas, dots, etc that could be surrounded by blanks (e.g. "one , two" should give [one][two]), it should be:
因为它是一个正则表达式，我假设你也不希望非字母数字字符，如逗号、点等可能被空格包围（例如，“一，二”应该给出 [one][two]），它应该是：
myString.split(/[\s\W]+/)
回答by Mike Manard
To get this working in Javascript, I had to do the following:
为了让它在 Javascript 中工作，我必须执行以下操作：
myString.split(/\s+/g)
回答by Felix Scheffer
Apache Commons Lang has a method to split a string with whitespace characters as delimiters:
Apache Commons Lang 有一种方法可以用空格字符作为分隔符来分割字符串：
StringUtils.split("abc def")
This might be easier to use than a regex pattern.
这可能比正则表达式模式更容易使用。
回答by RajeshVijayakumar
you can split a string by line break by using the following statement :
您可以使用以下语句按换行符拆分字符串：
String textStr[] = yourString.split("\r?\n");
you can split a string by Whitespace by using the following statement :
您可以使用以下语句按空格拆分字符串：
String textStr[] = yourString.split("\s+");
回答by jake_astub
Also you may have a UniCode non-breaking space xA0...
你也可能有一个 UniCode 不间断空格 xA0 ...
String[] elements = s.split("[\s\xA0]+"); //include uniCode non-breaking
回答by Olivia Liao
String str = "Hello World";
String res[] = str.split("\s+");
回答by Arrow
String string = "Ram is going to school";
String[] arrayOfString = string.split("\s+");
