如何通过 jQuery.ajax() 将多个参数传递给 PHP？
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How to pass multiple parameters by jQuery.ajax() to PHP?
提问by user866190
I have a simple load more style script that works fine on the index page, where only one parameter is sent via ajax
我有一个简单的加载更多样式脚本，它在索引页上运行良好，其中只有一个参数通过 ajax 发送
$(function() {//When the Dom is ready
$('.load_more').live("click",function() {//If user clicks on hyperlink with class name = load_more
var last_msg_id = $(this).attr("id");//Get the id of this hyperlink this id indicate the row id in the database
if(last_msg_id!='end'){//if the hyperlink id is not equal to "end"
$.ajax({//Make the Ajax Request
type: "POST",
url: "index_more.php",
data: "lastmsg="+ last_msg_id,
beforeSend: function() {
$('a.load_more').html('<img src="loading.gif" />');//Loading image during the Ajax Request
},
success: function(html){//html = the server response html code
$("#more").remove();//Remove the div with id=more
$("ul#updates").append(html);//Append the html returned by the server .
}
});
}
return false;
});
});
With this HTML/PHP
使用这个 HTML/PHP
<div id="more">
<a id="<?php echo $msg_id; ?>" class="load_more" href="#">more</a>
</div>
However, I want to add another php variable so that it can also work with particular categories, I have no problems writing the HTML and PHP but I am new to Jquery and struggling to edit the script to include the additional parameter if it is set. This is the HTML that I am thinking of using, just struggling with editing the JQuery
但是，我想添加另一个 php 变量，以便它也可以用于特定类别，我在编写 HTML 和 PHP 时没有问题，但我是 Jquery 的新手，并且正在努力编辑脚本以包含设置的附加参数。这是我正在考虑使用的 HTML，只是在编辑 JQuery 时苦苦挣扎
<div id="more"class="<?php echo $cat_id;?>">
<a id="<?php echo $msg_id;?>" class="load_more2" href="#">more</a>
</div>
As always any help is much appreciated!
与往常一样，非常感谢任何帮助！
回答by sberry
You can set
你可以设置
data = {onevar:'oneval', twovar:'twoval'}
And both key/value pairs will be sent.
并且将发送两个键/值对。
See Jquery ajax docs
If you look under the datasection, you can see that you can pass a query string like you are, an array, or an object. If you were to use the same method you already are using then your datavalue would be like "lastmsg="+ last_msg_id + "&otherthing=" + otherthing,
如果您查看该data部分的下方，您可以看到您可以像您一样传递查询字符串、数组或对象。如果您要使用您已经在使用的相同方法，那么您的data价值将是"lastmsg="+ last_msg_id + "&otherthing=" + otherthing，
回答by sberry
You can pass multiple URL params in the dataportion of your ajax call.
您可以在dataajax 调用的部分中传递多个 URL 参数。
data: "lastmsg="+ last_msg_id +"&otherparam="+ other_param
On the PHP side, you'd just process these as you already are.
在 PHP 方面，您只需按原样处理这些。
回答by Jignesh Manek
You can use this code:
您可以使用此代码：
$.ajax({//Make the Ajax Request
type: "POST",
url: "index_more.php",
data: {var1: "value1", var2: "value2"},
beforeSend: function() {
$('a.load_more').html('<img src="loading.gif" />');//Loading image during the Ajax Request
},
success: function(html){//html = the server response html code
$("#more").remove();//Remove the div with id=more
$("ul#updates").append(html);//Append the html returned by the server .
}
});
回答by Brijesh Kansagara
Try It:
尝试一下：
data: JSON.stringify({ lastmsg: last_msg_id, secondparam: second_param_value});
You can add more parameters separating them by comma (,).
您可以添加更多参数，以逗号 (,) 分隔它们。
