asp.net-mvc MVC 5 将视图渲染为字符串

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时间:2020-09-08 03:40:59  来源:igfitidea点击:

MVC 5 Render View to String

asp.net-mvcasp.net-mvc-5

提问by wh1sp3r

It seems, most code for rendering view into string doesn't work in MVC 5.

看来,将视图渲染为字符串的大多数代码在 MVC 5 中都不起作用。

I have latest MVC 5.1.2 templates and I am trying to render view into string.

我有最新的 MVC 5.1.2 模板,我正在尝试将视图呈现为字符串。

    public static String RenderViewToString(ControllerContext context, String viewPath, object model = null)
    {
        context.Controller.ViewData.Model = model;
        using (var sw = new StringWriter())
        {
            var viewResult = ViewEngines.Engines.FindView(context, viewPath, null);
            var viewContext = new ViewContext(context, viewResult.View, context.Controller.ViewData, context.Controller.TempData, sw);
            viewResult.View.Render(viewContext, sw);
            viewResult.ViewEngine.ReleaseView(context, viewResult.View);
            return sw.GetStringBuilder().ToString();
        }
    }

Well, it's working but its output contains lots of $ marks instead tags. I read something about it was fixed in RC version, but that's old news.

嗯,它正在工作,但它的输出包含很多 $ 标记而不是标签。我读到一些关于它在 RC 版本中已修复的内容,但那是旧消息。

Problem looks like this

问题看起来像这样

<$A$><h1></h1> 
<table</$A$><$B$> class=""</$B$><$C$>> <tbody</$C$><$D$></$D$><$E$>></tbody>
</table></$E$>

I would like to ask, how do you render views into string in latest MVC 5 template ? Thanks.

我想问一下,你如何在最新的 MVC 5 模板中将视图渲染成字符串?谢谢。

回答by wh1sp3r

Ok, seems I found a solution. Author of the idea is Yakir Manor.

好吧,看来我找到了解决方案。这个想法的作者是亚基尔庄园。

class FakeController : ControllerBase
{
    protected override void ExecuteCore() { }
    public static string RenderViewToString(string controllerName, string viewName, object viewData)
    {
        using (var writer = new StringWriter())
        {
            var routeData = new RouteData();
            routeData.Values.Add("controller", controllerName);
            var fakeControllerContext = new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://google.com", null), new HttpResponse(null))), routeData, new FakeController());
            var razorViewEngine = new RazorViewEngine();
            var razorViewResult = razorViewEngine.FindView(fakeControllerContext, viewName, "", false);

            var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(viewData), new TempDataDictionary(), writer);
            razorViewResult.View.Render(viewContext, writer);
            return writer.ToString();

        }
    }
}

It's a trick with fake context and response.

这是带有虚假上下文和响应的技巧。

Example:

例子:

String renderedHTML = RenderViewToString("Email", "MyHTMLView", myModel );

My file MyHTMLView.cstml is stored in Views/Email/MyHTMLView.cshtml. Email is a fake controller name.

我的文件 MyHTMLView.cstml 存储在 Views/Email/MyHTMLView.cshtml 中。电子邮件是一个虚假的控制器名称。

回答by Alok

following is the solution that works with session and areas on MVC5.

以下是适用于 MVC5 上的会话和区域的解决方案。

public class FakeController : ControllerBase
{
    protected override void ExecuteCore() { }
    public static string RenderViewToString(string controllerName, string viewName,string areaName, object viewData,RequestContext rctx)
    {
        try
        {
            using (var writer = new StringWriter())
            {
                var routeData = new RouteData();
                routeData.Values.Add("controller", controllerName);
                routeData.Values.Add("Area", areaName);
                routeData.DataTokens["area"] = areaName;

                var fakeControllerContext = new ControllerContext(rctx, new FakeController());
                //new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://google.com", null), new HttpResponse(null))), routeData, new FakeController());
                fakeControllerContext.RouteData = routeData;

                var razorViewEngine = new RazorViewEngine();

                var razorViewResult = razorViewEngine.FindView(fakeControllerContext, viewName, "", false);

                var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(viewData), new TempDataDictionary(), writer);

                razorViewResult.View.Render(viewContext, writer);
                return writer.GetStringBuilder().ToString();
                //use example
                //String renderedHTML = RenderViewToString("Email", "MyHTMLView", myModel );
                //where file MyHTMLView.cstml is stored in Views/Email/MyHTMLView.cshtml. Email is a fake controller name.
            }
        }
        catch (Exception ex)
        {
            //do your exception handling here
        }
    }
}

here is how you call this from another controller

这是你从另一个控制器调用它的方式

var modal = getModal(params);
return FakeController.RenderViewToString(controllerName, viewName, areaName, modal, this.Request.RequestContext);

using requestcontext we can easily pass current session in fakecontroller and render razor string.

使用 requestcontext 我们可以轻松地在 fakecontroller 中传递当前会话并呈现剃刀字符串。

回答by William Bosacker

I had an immediate need to return 6 partial views as strings in a JSON object. Instead of creating a static method, and passing all the unneeded parameters, I decided to add protected methods to our ControllerBase class that derives from Controller, and is used as the base class for all of our controllers.

我迫切需要将 6 个部分视图作为 JSON 对象中的字符串返回。我没有创建静态方法并传递所有不需要的参数,而是决定将受保护的方法添加到从 Controller 派生的 ControllerBase 类中,并用作我们所有控制器的基类。

Here is a fully functional ControllerBase class that provides this functionality, and works very similar to the PartialView() and View() methods that are in the Controller class. It includes the additions from @Alok.

这是一个提供此功能的全功能 ControllerBase 类,其工作方式与 Controller 类中的 PartialView() 和 View() 方法非常相似。它包括来自@Alok 的补充。

public abstract class ControllerBase : Controller
{
    #region PartialViewToString

    protected string PartialViewToString(string partialViewName, object model = null)
    {
        ControllerContext controllerContext = new ControllerContext(Request.RequestContext, this);

        return ViewToString(
            controllerContext,
            ViewEngines.Engines.FindPartialView(controllerContext, partialViewName) ?? throw new FileNotFoundException("Partial view cannot be found."),
            model
        );
    }

    #endregion

    #region ViewToString

    protected string ViewToString(string viewName, object model = null)
    {
        ControllerContext controllerContext = new ControllerContext(Request.RequestContext, this);

        return ViewToString(
            controllerContext,
            ViewEngines.Engines.FindView(controllerContext, viewName, null) ?? throw new FileNotFoundException("View cannot be found."),
            model
        );
    }

    protected string ViewToString(string viewName, string controllerName, string areaName, object model = null)
    {
        RouteData routeData = new RouteData();
        routeData.Values.Add("controller", controllerName);

        if (areaName != null)
        {
            routeData.Values.Add("Area", areaName);
            routeData.DataTokens["area"] = areaName;
        }

        ControllerContext controllerContext = new ControllerContext(HttpContext, routeData, this);

        return ViewToString(
            controllerContext,
            ViewEngines.Engines.FindView(controllerContext, viewName, null) ?? throw new FileNotFoundException("View cannot be found."),
            model
        );
    }

    #endregion

    #region Private Methods

    private string ViewToString(ControllerContext controllerContext, ViewEngineResult viewEngineResult, object model)
    {
        using (StringWriter writer = new StringWriter())
        {
            ViewContext viewContext = new ViewContext(
                controllerContext,
                viewEngineResult.View,
                new ViewDataDictionary(model),
                new TempDataDictionary(),
                writer
            );

            viewEngineResult.View.Render(viewContext, writer);

            return writer.ToString();
        }
    }

    #endregion
}

回答by stefan

@wh1sp3r answer works but for partial views I had to do the following minor changes:

@wh1sp3r 答案有效,但对于部分视图,我必须做以下小改动:

 string html = FakeController.RenderViewToString("**Controllername**", "~/views/**Controllername**/_AsdfPartialPage.cshtml", fem);


public static string RenderViewToString(string controllerName, string viewName, object viewData)
    {
        using (var writer = new StringWriter())
        {
            var routeData = new RouteData();
            routeData.Values.Add("controller", controllerName);
            var fakeControllerContext = new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://localhost", null), new HttpResponse(null))), routeData, new FakeController());
            var razorViewEngine = new RazorViewEngine();
            //var razorViewResult = razorViewEngine.FindView(fakeControllerContext, viewName, "", false);

            var razorViewResult = razorViewEngine.FindPartialView(fakeControllerContext, viewName,  false);

            var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(viewData), new TempDataDictionary(), writer);
            razorViewResult.View.Render(viewContext, writer);
            return writer.ToString();

        }
    }

回答by Ji?í ?trnácty

To render PartialView to string use this code:

要将 PartialView 渲染为字符串,请使用以下代码:

class FakeController: ControllerBase {
    protected override void ExecuteCore() { }
    public static string RenderViewToString(string controllerName, string viewName, object model) {
        using(var writer = new StringWriter()) {
            var routeData = new RouteData();
            routeData.Values.Add("controller", controllerName);
            var fakeControllerContext = new ControllerContext(new HttpContextWrapper(new HttpContext(new HttpRequest(null, "http://localhost", null), new HttpResponse(null))), routeData, new FakeController());
            var razorViewEngine = new RazorViewEngine();
            var razorViewResult = razorViewEngine.FindPartialView(fakeControllerContext, viewName, false);
            var viewContext = new ViewContext(fakeControllerContext, razorViewResult.View, new ViewDataDictionary(model), new TempDataDictionary(), writer);
            razorViewResult.View.Render(viewContext, writer);
            return writer.ToString();

        }
    }
}