php 删除 json_encode() 中的双引号
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Remove double quote in json_encode()
提问by jordiAnd
I want remove double quote in my json_encode, that is my code:
我想在我的 json_encode 中删除双引号，这是我的代码：
<?php
require_once 'config.inc.php';
//## Clase Base de Datos
require_once 'Database.class.php';
//## Obtengo los parametros pasados por el metodo GET
$params = $_REQUEST;
$db = new Database(DB_SERVER, DB_USER, DB_PASS, DB_DATABASE);
$db->connect();
$result = mysql_query("SELECT * from ranking WHERE posicion BETWEEN ".$params['pos_ini']." AND ".$params['pos_fi']) or die('Could not query');
if(mysql_num_rows($result)){
$array_json=array();
$filas = mysql_num_rows($result);
$columnas = mysql_num_fields($result);
for($i=0;$i<$filas;$i++)
{
$fila_dato = mysql_fetch_assoc($result);
for($k=0;$k<$columnas;$k++)
{
$campo = mysql_field_name($result,$k);
$campo = str_replace('\"', '', $campo);
$array_json[$i][$campo] = $fila_dato[$campo];
}
}
$array_final = json_encode($array_json);
$array_final = preg_replace('/"([a-zA-Z]+[a-zA-Z0-9]*)":/',':',$array_final);
echo $array_final;
} else {
echo '[]';
}
?>
My result is that:
我的结果是：
[{"id_posiciones":"1",posicion:"1",nick:"biwer",puntos:"1000",uid:"1",pais:"ES",idioma:"ES","device_version":"4"}]
I want to remove double quote of "id_posiciones" and "device_version" too.
我也想删除“id_posiciones”和“device_version”的双引号。
How can I do for the result is that:
我该怎么做才能得到结果：
[{id_posiciones:"1",posicion:"1",nick:"biwer",puntos:"1000",uid:"1",pais:"ES",idioma:"ES",device_version:"4"}]
采纳答案by Alex
If you add an underscore to your regex at the end it will do it.
如果最后在正则表达式中添加下划线，它就会这样做。
$array_final = preg_replace('/"([a-zA-Z]+[a-zA-Z0-9_]*)":/',':',$array_final);
I assume that's what that preg_replace is for anyway.
我认为这就是 preg_replace 的用途。
回答by Vijaysinh Parmar
You can use this bellow code to remove quote from numeric value.
您可以使用此波纹管代码从数值中删除引号。
http://php.net/manual/en/json.constants.php
http://php.net/manual/en/json.constants.php
It will work >=PHP 5.3.
它将工作>=PHP 5.3。
$encoded = json_encode($data, JSON_NUMERIC_CHECK);
回答by hek2mgl
Replace this line:
替换这一行：
$array_final = preg_replace('/"([a-zA-Z]+[a-zA-Z0-9]*)":/',':',$array_final);
by:
经过：
$array_final = preg_replace('/"([a-zA-Z_]+[a-zA-Z0-9_]*)":/',':',$array_final);
Note that the regex class [a-zA-Z] does not match the '_'
请注意，正则表达式类 [a-zA-Z] 与“_”不匹配
回答by Ghostman
You can use $.parseJSONto parse the string and create a Javascript object from it, or better yet use a method like $.getJSONto get it
您可以使用$.parseJSON来解析字符串并从中创建一个 Javascript 对象，或者更好地使用类似的方法$.getJSON来获取它
回答by Manmeet Khurana
// use can use addslashes() function for storing in mysql database
// or remove slashes u can use stripslashes() function.
$json_array = array(
'title' => 'Example string\'s with "special" characters'
);
echo $json_decode =addslashes(json_encode($json_array));
output-{\"title\":\"Example string\'s with \\"special\\" characters\"}
