bash 如何在bash中捕获curl的输出到变量
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How to capture the output of curl to variable in bash
提问by frazman
So, lets say I have the following command:
所以，假设我有以下命令：
curl -I http://google.com | head -n 1| cut -d $' ' -f2
This will capture the http status code?? Now I want to assign this to variable.. in bash script
这将捕获 http 状态代码？现在我想将它分配给变量.. 在 bash 脚本中
like output = "curl -I http://localhost:8088/tracks?key=9 | head -n 1| cut -d $' ' -f2"
or something like that..
或类似的东西..
How do I assign the response of above command to a variable called output in bash? Thanks
如何将上述命令的响应分配给 bash 中名为 output 的变量？谢谢
回答by
You have two options. Surrounding the invocation in back ticks or $(), like so:
你有两个选择。用反勾号或围绕调用$()，像这样：
output=`curl -I http://google.com | head -n 1| cut -d $' ' -f2`
echo $output;
output=$(curl -I http://google.com | head -n 1| cut -d $' ' -f2)
