为什么 Laravel REST 控制器 $request->input 为 NULL？
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Why Laravel REST controller $request->input is NULL?
提问by TomR
I am following tutorial http://www.tutorials.kode-blog.com/laravel-5-angularjs-tutorialand I have managed to write the similar method for my controller:
我正在关注教程http://www.tutorials.kode-blog.com/laravel-5-angularjs-tutorial并且我设法为我的控制器编写了类似的方法：
public function update(Request $request, $id) {
$employee = Employee::find($id);
$employee->name = $request->input('name');
//...
$employee->save();
return "Sucess updating user #" . $employee->id;
}
It is thought in tutorial that this code works but in reality var_dump($request->input) gives NULL. So - what $request variable should I use for getting the body of the request? I made var_dump($request) but the structure is unmanageably large. Actually I am suscpicous about this tutorial - do we really need to list all the fields in the standard update procedure?
在教程中认为此代码有效，但实际上 var_dump($request->input) 给出了 NULL。那么 - 我应该使用什么 $request 变量来获取请求的正文？我做了 var_dump($request) 但结构太大了。实际上，我对本教程持怀疑态度 -我们真的需要列出标准更新程序中的所有字段吗？
回答by swatkins
You can access the input data with:
您可以通过以下方式访问输入数据：
$input = $request->all();
https://laravel.com/docs/5.2/requests#retrieving-input
https://laravel.com/docs/5.2/requests#retrieving-input
However, I've also had to get the input in this manner when using AngularJS $httpmodule:
但是，在使用 AngularJS$http模块时，我也必须以这种方式获取输入：
$input = file_get_contents('php://input');
回答by jignesh patel
for get all input
获取所有输入
try it
尝试一下
$request = \Input::all();
回答by Akshay Khale
If you want to fetch individual parameters from request object the you can do that with input Methodof Request Class.
如果您想从请求对象中获取单个参数，您可以使用请求类的输入方法来实现。
$request->input("parameter_name");
$request->input("parameter_name");
But if you want to fetch all request parameters then you can use allmethod which will return you an array of all the request key-value pairs
但是如果你想获取所有请求参数，那么你可以使用all方法，它会返回一个包含所有请求键值对的数组
$request->all()
$request->all()
The thing you are missed is, you are calling $request->inputwhich is null because inputis methodof Request class and not a property
你错过的事情是，你在呼唤$request->input它为null，因为input是方法请求类的，而不是一个属性
