javascript 未捕获的错误:不变违规:React.render():无效的组件元素

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时间:2020-10-28 12:24:56  来源:igfitidea点击:

Uncaught Error: Invariant Violation: React.render(): Invalid component element

javascriptreactjs

提问by wolfgang

I'm a react newbie

我是一个反应新手

and I'm Creating a simple class and function and rendering to the body.

我正在创建一个简单的类和函数并渲染到主体。

However,

然而,

I get an Uncaught Error: Invariant Violation: React.render(): Invalid component element.

我得到一个 Uncaught Error: Invariant Violation: React.render(): Invalid component element.

<script src="https://fb.me/react-0.13.3.js"></script>
<script src="https://fb.me/JSXTransformer-0.13.3.js"></script>
<script src="https://code.jquery.com/jquery-2.1.3.min.js"></script>
<script type="text/jsx">

    var HelloWorld = React.createClass({
        render: function() {
            return <div>Hello, world!</div>;
        }
    });

    React.render(new HelloWorld(), document.body);

</script>


<body>

</body>
</html>

Any ideas on what is wrong?

关于什么是错的任何想法?

回答by wolfgang

use <HelloWorld/>instead of new HelloWorld()

使用<HelloWorld/>代替new HelloWorld()

回答by brettish

Change React.render(new HelloWorld(), document.body);to React.render(React.createElement(HelloWorld), document.body);and it should work. The React.renderfunction expects a ReactElementwhich you can create via React.createElement.

更改React.render(new HelloWorld(), document.body);React.render(React.createElement(HelloWorld), document.body);它应该可以工作。 The React.render函数需要 a ReactElement,您可以通过React.createElement.

You can see the docs here along with some other useful functions: https://facebook.github.io/react/docs/top-level-api.html

您可以在此处查看文档以及其他一些有用的功能:https: //facebook.github.io/react/docs/top-level-api.html

回答by corlaez

Writting the render method of your component like this will launch the same Error:

像这样编写组件的渲染方法将启动相同的错误:

...
render: function() {
  return      //you need "return <div>" for this to work.
    <div> 
      <h4>MyComponent message</h4>
    </div>;
}

The shown code will trigger the same error because there is now element next to the return (you shouldn't break the line there).

显示的代码将触发相同的错误,因为现在返回旁边有元素(您不应该在那里断行)。