Java 用于动态端点的 Apache CXF 客户端

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时间:2020-08-13 15:38:07  来源:igfitidea点击:

Apache CXF Client for Dynamic Endpoints

javaweb-servicescxfclient-side

提问by andyczerwonka

I'm now using Apache CXF as a web services client for a .NET service to get around NTLM authentication. It works great, but I'm wondering why I can't seem to be able to set the web service target endpoint. CXF seems to want the WSDL at runtime for some strange reason - not sure. It takes the physical endpoint from the WSDL, which works fine in test environments I guess, but at deployment time it's sure to change.

我现在使用 Apache CXF 作为 .NET 服务的 Web 服务客户端来绕过 NTLM 身份验证。它工作得很好,但我想知道为什么我似乎无法设置 Web 服务目标端点。出于某种奇怪的原因,CXF 似乎希望在运行时使用 WSDL - 不确定。它从 WSDL 获取物理端点,我猜它在测试环境中工作正常,但在部署时它肯定会改变。

Here's some code to demonstrate:

下面是一些代码来演示:

        MyWebServices service = new MyWebServices ();
        MyWebServicesSoap port = service.getMyWebServicesSoap12();

        // Turn off chunking so that NTLM can occur
        Client client = ClientProxy.getClient(port);
        HTTPConduit http = (HTTPConduit) client.getConduit();
        HTTPClientPolicy httpClientPolicy = new HTTPClientPolicy();
        httpClientPolicy.setConnectionTimeout(36000);
        httpClientPolicy.setAllowChunking(false);
        http.setClient(httpClientPolicy);

        port.doSomethingUseful();

Again, there is no place that I can see in the CXF client API that allows me to set the service endpoint. Not that I can see anyway. In this case, the target is http://localhost/integration/webservices/mywebservices.asmx, but I could be anywhere. Surely this pedestrian problem is solved somehow?

同样,在 CXF 客户端 API 中没有任何地方可以让我设置服务端点。反正我看不到。在这种情况下,目标是http://localhost/integration/webservices/mywebservices.asmx,但我可以在任何地方。当然,这个行人问题以某种方式解决了?

采纳答案by Kevin

Try the following:

请尝试以下操作:

MyWebServicesSoap port = service.getMyWebServicesSoap12();
BindingProvider provider = (BindingProvider) port;
provider.getRequestContext().put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY, endpoint); 

Alternatively, MyWebServicesmight have other getXXX methods that take a URL for the WSDL location

或者,MyWebServices可能有其他获取 WSDL 位置 URL 的 getXXX 方法

回答by Shahzad Mughal

Working in cxf 2.6.1

在 cxf 2.6.1 中工作

Client client = ClientProxy.getClient(port);
client.getRequestContext().put(Message.ENDPOINT_ADDRESS, "http://some-valid-endpoint") ;

回答by Fholisani Mashegana

This worked for me.

这对我有用。

String customerEndPoint = "https://localhost:8080/customerService/v1"

customerWebService = service.getCustomerWebServicePort();

((BindingProvider) customerWebService).getRequestContext()
                        .put(BindingProvider.ENDPOINT_ADDRESS_PROPERTY,
                                customerEndPoint);