Javascript 匹配最多 9 位整数的正则表达式
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Regular expression to match integers up to 9 digits
提问by t0mcat
I want to create a regular expression where only numbers are allowed with max length 9 and no minimum length. I came up with \d{9}[0-9]but it isn't working.
我想创建一个正则表达式，其中只允许最大长度为 9 且没有最小长度的数字。我想出来了，\d{9}[0-9]但没有用。
回答by vcsjones
You're close. Try this:
你很接近。尝试这个：
^\d{0,9}$
The ^ and $ match the beginning and the end of the text, respectively. \d{0,9}matches anywhere in the string, so d0000would pass because it would match the 0000even though there is a d in it, which I don't think you want. That's why they ^$ should be in there.
^ 和 $ 分别匹配文本的开头和结尾。\d{0,9}匹配字符串中的任何位置，所以d0000会通过，因为0000即使其中有广告，它也会匹配，我认为您不想要。这就是为什么他们 ^$ 应该在那里。
回答by NT3RP
Regular expressions can be tricky; what you've written does the following:
正则表达式可能很棘手；你写的内容如下：
\d- digit\d{9}- exactly 9 digits\d{9}[0-9]- exactly 9 digits, followed by something between 0 and 9
\d- 数字\d{9}- 正好 9 位\d{9}[0-9]- 正好是 9 位数字，后跟 0 到 9 之间的数字
If you want no minimum limit of length, but a maximum length of 9, you probably want the following regular expression:
如果您不需要最小长度限制，但最大长度为 9，您可能需要以下正则表达式：
\d{0,9}- 0 to 9 digits
\d{0,9}- 0 到 9 位数字
回答by Jan
I think It should be 1to 9 digits:
我认为它应该是1到 9 位数字：
^\d{1,9}$
回答by Brian Fisher
It looks like you were close, try \d{0,9}.
看起来你很接近，试试吧\d{0,9}。
