如何从 PHP 中的 json 响应中按键提取值
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How to extract value by key from json response in PHP
提问by user1610208
I'm using getResponse api for getting updated about subscribers.
This is what is printing after var_dump($result);
我正在使用 getResponse api 来获取有关订阅者的更新信息。这是打印后的内容var_dump($result);
object(stdClass)#2 (1) {
["updated"]=>
int(1)
}
How do i extract / decode / encode the result to request the key: "update" and get it's value: 1 ?
我如何提取/解码/编码结果以请求密钥：“更新”并获取其值：1？
Thanks
谢谢
回答by reshetech
// json object.
$contents = '{"firstName":"John", "lastName":"Doe"}';
// Option 1: through the use of an array.
$jsonArray = json_decode($contents,true);
$key = "firstName";
$firstName = $jsonArray[$key];
// Option 2: through the use of an object.
$jsonObj = json_decode($contents);
$firstName = $jsonObj->$key;
回答by Elias Van Ootegem
It's already decoded, as you can see on the man pages, the default behavior of json_decodeis to decode a JSON string to an instance of stdClass, if you want an assoc array, simply write:
它已经被解码，正如您在手册页上看到的那样，默认行为json_decode是将 JSON 字符串解码为 的实例stdClass，如果您想要一个关联数组，只需编写：
$string = '{"updated":1}';
$array = json_decode($string, true);
echo $array['updated'];
But you can just access the updatedvalue on the object, because it's just a public property anyway:
但是您只能访问updated对象上的值，因为无论如何它只是一个公共属性：
$obj = json_decode($string);
echo $obj->updated;
