合并 Python 字典
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merging Python dictionaries
提问by Joey
I am trying to merge the following python dictionaries as follow:
我正在尝试按如下方式合并以下 python 词典：
dict1= {'paul':100, 'john':80, 'ted':34, 'herve':10}
dict2 = {'paul':'a', 'john':'b', 'ted':'c', 'peter':'d'}
output = {'paul':[100,'a'],
'john':[80, 'b'],
'ted':[34,'c'],
'peter':[None, 'd'],
'herve':[10, None]}
Is there an efficient way to do this?
有没有一种有效的方法来做到这一点？
回答by Alex Martelli
output = {k: [dict1[k], dict2.get(k)] for k in dict1}
output.update({k: [None, dict2[k]] for k in dict2 if k not in dict1})
回答by Nadia Alramli
This will work:
这将起作用：
{k: [dict1.get(k), dict2.get(k)] for k in set(dict1.keys() + dict2.keys())}
Output:
输出：
{'john': [80, 'b'], 'paul': [100, 'a'], 'peter': [None, 'd'], 'ted': [34, 'c'], 'herve': [10, None]}
回答by John La Rooy
In Python2.7or Python3.1you can easily generalise to work with any number of dictionaries using a combination of list, set and dict comprehensions!
在Python2.7或Python3.1 中，您可以使用列表、集合和字典推导式的组合轻松地概括以使用任意数量的字典！
>>> dict1 = {'paul':100, 'john':80, 'ted':34, 'herve':10}
>>> dict2 = {'paul':'a', 'john':'b', 'ted':'c', 'peter':'d'}
>>> dicts = dict1,dict2
>>> {k:[d.get(k) for d in dicts] for k in {k for d in dicts for k in d}}
{'john': [80, 'b'], 'paul': [100, 'a'], 'peter': [None, 'd'], 'ted': [34, 'c'], 'herve': [10, None]}
Python2.6doesn't have set comprehensions or dict comprehensions
Python2.6没有集合推导式或字典推导式
>>> dict1 = {'paul':100, 'john':80, 'ted':34, 'herve':10}
>>> dict2 = {'paul':'a', 'john':'b', 'ted':'c', 'peter':'d'}
>>> dicts = dict1,dict2
>>> dict((k,[d.get(k) for d in dicts]) for k in set(k for d in dicts for k in d))
{'john': [80, 'b'], 'paul': [100, 'a'], 'peter': [None, 'd'], 'ted': [34, 'c'], 'herve': [10, None]}
回答by asdfg
In Python3.1,
在 Python3.1 中，
output = {k:[dict1.get(k),dict2.get(k)] for k in dict1.keys() | dict2.keys()}
output = dict((k,[dict1.get(k),dict2.get(k)]) for k in set(dict1.keys() + dict2.keys()))