MOXy JAXB javax.xml.bind.PropertyException
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MOXy JAXB javax.xml.bind.PropertyException
提问by Gergely Fehérvári
I followed this example: http://wiki.eclipse.org/EclipseLink/Examples/MOXy/JSON_Twitter
我跟着这个例子：http: //wiki.eclipse.org/EclipseLink/Examples/MOXy/JSON_Twitter
Now I have this class:
现在我有这门课：
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBElement;
import javax.xml.bind.Marshaller;
import javax.xml.bind.Unmarshaller;
import javax.xml.transform.stream.StreamSource;
import org.eclipse.persistence.jaxb.MarshallerProperties;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Foo.class);
Unmarshaller unmarshaller = jc.createUnmarshaller();
unmarshaller.setProperty("eclipselink.media-type", "application/json");
unmarshaller.setProperty("eclipselink.json.include-root", false);
StreamSource source = new StreamSource("http://test.url/path/to/resource");
JAXBElement<Foo> jaxbElement = unmarshaller.unmarshal(source, Foo.class);
System.out.println(jaxbElement.getValue().getFoo());
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.setProperty(MarshallerProperties.MEDIA_TYPE, "application/json");
marshaller.setProperty("eclipselink.json.include-root", false);
marshaller.marshal(jaxbElement, System.out);
}
}
And I have jaxb.properties:
我有jaxb.properties：
javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.JAXBContextFactory
If I run this code, I get:
如果我运行此代码，我会得到：
Exception in thread "main" javax.xml.bind.PropertyException: name: eclipselink.media-type value: application/json
at javax.xml.bind.helpers.AbstractUnmarshallerImpl.setProperty(AbstractUnmarshallerImpl.java:352)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.setProperty(UnmarshallerImpl.java:450)
at com.example.JavaSEClient.main(JavaSEClient.java:19)
How can I fix this?
我怎样才能解决这个问题？
I searched SO and Google, these answers are not working:
我搜索了 SO 和 Google，这些答案不起作用：
PropertyException when setting Marshaller property with eclipselink.media-type value: application/jsonJAXB javax.xml.bind.PropertyException
使用 eclipselink.media-type 值设置 Marshaller 属性时出现 PropertyException：application/json JAXB javax.xml.bind.PropertyException
采纳答案by bdoughan
You need to make sure that your jaxb.propertiesfile is in the same package as the domain classes you used to bootstrap the JAXBContext, and that EclipseLink MOXy is on your class path.
您需要确保您的jaxb.properties文件与用于引导JAXBContext.
If you are using Maven, then the jaxb.propertiesfile should be under the following location assuming Foois in a package called com.example.Foo:
如果您使用的是 Maven，则该jaxb.properties文件应位于以下位置，假设Foo位于名为 的包中com.example.Foo：
- src/main/resources/com/example/foo/jaxb.properties
- src/main/java/com/example/foo/Foo.class
- src/main/resources/com/example/foo/jaxb.properties
- src/main/java/com/example/foo/Foo.class
For a full example see:
有关完整示例，请参见：
