java 没有当前上下文的opengl es api
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opengl es api with no current context
提问by Serguei Fedorov
I have looked through the solutions and haven't really found one. I am getting this error because it seems like the execution happens outside of the gl thread. However I am not sure how to fix this. The code is as follows:
我已经浏览了解决方案，但还没有真正找到一个。我收到此错误是因为执行似乎发生在 gl 线程之外。但是我不知道如何解决这个问题。代码如下：
public shape()
{
super();
vertexShader = Shader.loadShader(GLES20.GL_VERTEX_SHADER, vertexShaderCode); //<============
fragmentShader = Shader.loadShader(GLES20.GL_FRAGMENT_SHADER, fragmentShaderCode);
ByteBuffer buffer = ByteBuffer.allocateDirect(getCoordinates().length * 4);
buffer.order(ByteOrder.nativeOrder());
vertexBuffer = buffer.asFloatBuffer();
vertexBuffer.put(getCoordinates());
vertexBuffer.position(0);
ByteBuffer drawListBuffer = ByteBuffer.allocateDirect(getOrderOfDraw().length * 2);
drawListBuffer.order(ByteOrder.nativeOrder());
listBuffer = drawListBuffer.asShortBuffer();
listBuffer.put(getOrderOfDraw());
listBuffer.position(0);
mProgram = GLES20.glCreateProgram(); // create empty OpenGL Program
GLES20.glAttachShader(mProgram, vertexShader); // add the vertex shader to program
GLES20.glAttachShader(mProgram, fragmentShader); // add the fragment shader to program
GLES20.glLinkProgram(mProgram);
}
and the calling renderer is
和调用渲染器是
Square square = new Square(5, 5);
public void onDrawFrame(GL10 unused)
{
unused.glLoadIdentity();
unused.glClear(GLES20.GL_COLOR_BUFFER_BIT);
square.Draw();
}
Square extends from shape
正方形从形状延伸
回答by Tim
If that new Square(5,5);is not part of any of the opengl callbacks (I assume you're using a glSurfaceView), then I don't think it runs on the OpenGL thread. It will be executed when your glSurfaceView is created, which I believe is on the main android thread.
如果这new Square(5,5);不是任何 opengl 回调的一部分（我假设您使用的是 glSurfaceView），那么我认为它不会在 OpenGL 线程上运行。它将在您的 glSurfaceView 创建时执行，我相信它是在主 android 线程上。
Try moving new Square(5,5);inside of onSurfaceCreated.
尝试new Square(5,5);在onSurfaceCreated.
