PHP 函数替换第 (i) 个位置的字符
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PHP function to replace a (i)th-position character
提问by vikmalhotra
Is there a function in PHP that takes in a string, a number (i), and a character (x), then replaces the character at position (i) with (x)?
PHP 中是否有一个函数接受一个字符串、一个数字 ( i) 和一个字符 ( x)，然后将位置 ( i)处的字符替换为( x)？
If not, can somebody help me in implementing it?
如果没有，有人可以帮助我实施它吗？
回答by codaddict
$str = 'bar';
$str[1] = 'A';
echo $str; // prints bAr
or you could use the library function substr_replaceas:
或者您可以将库函数substr_replace用作：
$str = substr_replace($str,$char,$pos,1);
回答by zerkms
I amazed why no one remember about substr_replace()
我很惊讶为什么没有人记得substr_replace()
substr_replace($str, $x, $i, 1);
回答by alex
Codaddict is correct, but if you wanted a function, you could try...
Codacci 是正确的，但如果你想要一个功能，你可以尝试......
function updateChar($str, $char, $offset) {
if ( ! isset($str[$offset])) {
return FALSE;
}
$str[$offset] = $char;
return $str;
}
回答by Emil Vikstr?m
function replace_char($string, $position, $newchar) {
if(strlen($string) <= $position) {
return $string;
}
$string[$position] = $newchar;
return $string;
}
It's safe to treat strings as arrays in PHP, as long as you don't try to change chars after the end of the string. See the manual on strings:
在 PHP 中将字符串视为数组是安全的，只要您不尝试在字符串结束后更改字符。请参阅有关字符串的手册：
回答by Amorim
implode(':', str_split('1300', 2));
returns:
返回：
13:00
13:00
Also very nice for some credit card numbers like Visa:
对于像 Visa 这样的一些信用卡号码也非常好：
implode(' ', str_split('4900000000000000', 4));
returns:
返回：
4900 0000 0000 0000
4900 0000 0000 0000
