Javascript 推特用户名的正则表达式
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Regular expression for twitter username
提问by ppp
I need a javascript regular expression to match twitter usernames.
我需要一个 javascript 正则表达式来匹配 twitter 用户名。
The username is entered by the user while signing up, so I don't want to distract them with too many error notifications. Because of that, I need the expression to match valid usernames regardles if they have the @ before the username or not.
用户名是用户在注册时输入的，所以我不想让太多的错误通知分散他们的注意力。因此，我需要表达式来匹配有效的用户名，不管他们在用户名之前是否有@。
Twitter usernames can contain latin characters, underscores and numbers, and the only limitation is the can be up to 15 characters long. ( but I need the regex to match 16 characters as well, in case someone enters the @ before the username ).
Twitter 用户名可以包含拉丁字符、下划线和数字，唯一的限制是最长可达 15 个字符。（但我还需要正则表达式来匹配 16 个字符，以防有人在用户名之前输入 @ ）。
回答by asenovm
This should do:
^@?(\w){1,15}$
这应该做：
^@?(\w){1,15}$
回答by rayfranco
This is the best solution I found yet to replace multiple occurrences of a twitter username.
这是我发现的最好的解决方案，可以替换多次出现的 twitter 用户名。
The regex doing the trick is /(^|[^@\w])@(\w{1,15})\b/. I am catching what stand behind the @ character so I can replace the username correctly. And I am using global match flag (g) so it will replace all occurrences.
asenovmanswer is simple, but will not work in most user input contexts, as techexpertis explaining in his comment.
做这个伎俩的正则表达式是/(^|[^@\w])@(\w{1,15})\b/. 我正在捕捉@ 字符后面的内容，以便我可以正确替换用户名。我正在使用全局匹配标志 (g)，因此它将替换所有出现的。
asenovm答案很简单，但在大多数用户输入上下文中不起作用，正如techexpert在他的评论中解释的那样。
var output,
text = "@RayFranco is answering to @AnPel, this is a real '@username83' but this is [email protected], and this is a @probablyfaketwitterusername",
regex = /(^|[^@\w])@(\w{1,15})\b/g,
replace = '<a href="http://twitter.com/">@</a>';
output = text.replace( regex, replace );
console.log ( output );
This is giving me what I expected (tested with node v0.9.1):
这给了我我所期望的（用节点 v0.9.1 测试）：
@RayFrancois answering to @AnPel, this is a real '@username83' but this is [email protected], and this is a @probablyfaketwitterusername
@RayFranco正在回复@AnPel，这是一个真正的“ @username83”，但这是 [email protected]，这是一个 @probablyfaketwitterusername
This is based on Twitter "specs" for username:
这是基于用户名的 Twitter“规范”：
Your username cannot be longer than 15 characters. Your real name can be longer (20 characters), but usernames are kept shorter for the sake of ease. A username can only contain alphanumeric characters (letters A-Z, numbers 0-9) with the exception of underscores, as noted above. Check to make sure your desired username doesn't contain any symbols, dashes, or spaces.
您的用户名不能超过 15 个字符。您的真实姓名可以更长（20 个字符），但为了方便起见，用户名会保持较短。如上所述，用户名只能包含字母数字字符（字母 AZ、数字 0-9），下划线除外。检查以确保您想要的用户名不包含任何符号、破折号或空格。
Hope this helps.
希望这可以帮助。
回答by Rodrigo Polo
A short an easy way to do it:
一个简单的方法来做到这一点：
function validTwitteUser(sn) {
return /^[a-zA-Z0-9_]{1,15}$/.test(sn);
}
回答by suryaveer gaur
@[a-zA-Z0-9_]{0,15}
@[a-zA-Z0-9_]{0,15}
You can use above regular expression to sort of the twitter usernames from a mixed set of data
您可以使用上面的正则表达式从一组混合数据中对 Twitter 用户名进行排序
回答by Ernane Luis
I think the correct regex is this /^@(\w){1,15}/gwithout the ? on @(at)
我认为正确的正则表达式是/^@(\w){1,15}/g没有 ? 在@(at)
回答by Will Schoenberger
It may be more than you need but I found this in another post "regex how to replace twitter links". Wraps @usernames, #hashtags and urls. Working well for me.
它可能超出您的需要，但我在另一篇文章“正则表达式如何替换 twitter 链接”中找到了这一点。包裹@usernames、#hashtags 和 url。对我来说工作得很好。
function processTweetLinks(text) {
var exp = /(\b(https?|ftp|file):\/\/[-A-Z0-9+&@#\/%?=~_|!:,.;]*[-A-Z0-9+&@#\/%=~_|])/gi;
text = text.replace(exp, "<a href='' target='_blank'></a>");
exp = /(^|\s)#(\w+)/g;
text = text.replace(exp, "<a href='https://twitter.com/hashtag/?src=hash' target='_blank'>#</a>");
exp = /(^|\s)@(\w+)/g;
text = text.replace(exp, "<a href='http://www.twitter.com/' target='_blank'>@</a>");
return text;
}
回答by Osman Turan
To exclude "non-latin"characters, you have to use: ^@?([a-zA-Z0-9_]){1,15}$. Because, \waccepts "any word characters". And non-latin characters qualifies this condition. So, it matches even ü?like Turkish characters as well.
要排除“非拉丁”字符，您必须使用：^@?([a-zA-Z0-9_]){1,15}$。因为，\w接受“任何单词字符”。非拉丁字符符合此条件。因此，它甚至ü?像土耳其语字符一样匹配。
