ios 在Objective-C中替换字符串中的一个字符
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Replacing one character in a string in Objective-C
提问by RanLearns
Hoping somebody can help me out - I would like to replace a certain character in a string and am wondering what is the best way to do this?
希望有人可以帮助我 - 我想替换字符串中的某个字符，并且想知道这样做的最佳方法是什么？
I know the location of the character, so for example, if I want to change the 3rd character in a string from A to B - how would I code that?
我知道字符的位置，例如，如果我想将字符串中的第三个字符从 A 更改为 B - 我将如何编码？
回答by theChrisKent
If it is always the same character you can use:
如果它总是相同的字符，您可以使用：
stringByReplacingOccurrencesOfString:withString:
If it is the same string in the same location you can use:
如果它在同一位置是相同的字符串，您可以使用：
stringByReplacingOccurrencesOfString:withString:options:range:
If is just a specific location you can use:
如果只是一个特定的位置，您可以使用：
stringByReplacingCharactersInRange:withString:
Documentation here: https://developer.apple.com/documentation/foundation/nsstring
此处的文档：https: //developer.apple.com/documentation/foundation/nsstring
So for example:
例如：
NSString *someText = @"Goat";
NSRange range = NSMakeRange(0,1);
NSString *newText = [someText stringByReplacingCharactersInRange:range withString:@"B"];
newText would equal "Boat"
newText 等于“Boat”
回答by MaxEcho
NSString *str = @"123*abc";
str = [str stringByReplacingOccurrencesOfString:@"*" withString:@""];
//str now 123abc
回答by Zakaria
Here is the code:
这是代码：
[aString stringByReplacingCharactersInRange:NSMakeRange(3,1) withString:@"B"];
回答by Bourne
Use the replaceCharactersInRange: withString:message on a NSMutableStringobject.
replaceCharactersInRange: withString:在NSMutableString对象上使用消息。
