python - 基于部分字符串在列表中查找索引位置
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python - find index position in list based of partial string
提问by L Shaw
mylist = ["aa123", "bb2322", "aa354", "cc332", "ab334", "333aa"]
I need the index position of all items that contain 'aa'. I'm having trouble combining enumerate() with partial string matching. I'm not even sure if I should be using enumerate.
我需要包含“aa”的所有项目的索引位置。我在将 enumerate() 与部分字符串匹配相结合时遇到了麻烦。我什至不确定是否应该使用枚举。
I just need to return the index positions: 0,2,5
我只需要返回索引位置：0,2,5
采纳答案by StoryTeller - Unslander Monica
indices = [i for i, s in enumerate(mylist) if 'aa' in s]
回答by pemistahl
Your idea to use enumerate()was correct.
您使用的想法enumerate()是正确的。
indices = []
for i, elem in enumerate(mylist):
if 'aa' in elem:
indices.append(i)
Alternatively, as a list comprehension:
或者，作为列表理解：
indices = [i for i, elem in enumerate(mylist) if 'aa' in elem]
回答by TerryA
Without enumerate():
没有enumerate()：
>>> mylist = ["aa123", "bb2322", "aa354", "cc332", "ab334", "333aa"]
>>> l = [mylist.index(i) for i in mylist if 'aa' in i]
>>> l
[0, 2, 5]
回答by user11167492
spell_list = ["Tuesday", "Wednesday", "February", "November", "Annual", "Calendar", "Solstice"]
index=spell_list.index("Annual")
print(index)
