Facebook PHP 抛出异常“（#803）您请求的某些别名不存在”
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Facebook PHP throwing exception "(#803) Some of the aliases you requested do not exist"
提问by Chris Masterton
I have a valid and authenticated user, but when posting to their wall from our PHP web app it returns:
我有一个有效且经过身份验证的用户，但是当从我们的 PHP Web 应用程序发布到他们的墙上时，它返回：
Fatal error: Uncaught OAuthException: (#803) Some of the aliases you requested do not exist: xxxxxxxxxxxxx","name":"xxxxxxx
致命错误：未捕获的 OAuthException：（#803）您请求的某些别名不存在：xxxxxxxxxxxxx","name":"xxxxxxx
I have 24 other users that can post with no issues. And I can see the user exists by going to https://graph.facebook.com/xxxxxxxxxxxxx
我还有 24 个其他用户可以毫无问题地发帖。我可以通过访问https://graph.facebook.com/xxxxxxxxxxxxx看到用户存在
Here is the code:
这是代码：
$fb_user_id = $row[0]; // loaded from DB
$facebook_token = $row[1]; // loaded from DB
$result = $facebook->api('/' . $fb_user_id. '/feed/',
'post',
array('access_token' => $facebook_token,
'message' => $postMessage,
'name' => 'Product name',
'caption' => 'Accomplished!',
'link' => 'http://www.xxxxxxx.com/',
'description' => $postMessage,
'picture' => 'http://www.xxxxxxx.com/images/productImage.png'));
Any ideas why the Facebook API thinks this user does not exist?
为什么 Facebook API 认为该用户不存在的任何想法？
回答by Daniel
I had this issue, later I realised I was saving the uid in my database as an integer, however, new facebook profiles have very long uids, such as : 100004409446248, this was not a value I could save as an integerin my mysql database, I changed this to treat it as a varchar, so now there's no issue
我有这个问题，后来我意识到我保存在我的数据库中的UID作为integer，然而，新的Facebook个人主页有很长的UID，如：100004409446248，这不是一个值，我可以保存为integer我的MySQL数据库，我改变this 将其视为 a varchar，所以现在没有问题
回答by 0xAli
This question Getting list of Facebook friends with latest APIsuggests
这个问题使用最新的 API 获取 Facebook 好友列表建议
$friends = $facebook->api('/me/friends');
$friends = $facebook->api('/me/friends');
回答by anov
I wrote two library routine for get integer querystrings. Similar to Dainel's experience when I use the intval()function, I get an invalid Facebook id cause produce that error.
我写了两个库例程来获取整数查询字符串。与我使用该intval()功能时 Dainel 的经历类似，我得到了一个无效的 Facebook id，导致产生该错误。
Code:
代码：
function get_int($field) {
$value = 0;
if(isset($_GET[$field])) $value = intval($_GET[$field]);
return $value;
}
I use the get_str for facebook_id and problem was gone.
我将 get_str 用于 facebook_id 并且问题消失了。
function get_str($field) {
$value = '';
if(isset($_GET[$field])) $value = $_GET[$field];
return $value;
}
回答by elo
Define APP ID as integer, not string!
将APP ID定义为整数，而不是字符串！
