php in_array() 期望参数 2 是数组，给定 null
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in_array() expects parameter 2 to be array, null given
提问by Gianni Alessandro
I made a web-application with Symfony2, and I'm using PUGX User Bundle and FosUserBundle to manage 2 different users.
我用 Symfony2 制作了一个网络应用程序，我使用 PUGX User Bundle 和 FosUserBundle 来管理 2 个不同的用户。
This is one of the two user:
这是两个用户之一：
/**
* @ORM\Entity
* @ORM\Table(name="user_Operator")
* @ORM\HasLifecycleCallbacks()
* @UniqueEntity(fields = "username", targetClass = "Acme\ManagementBundle\Entity\User", message="Username already_used")
* @UniqueEntity(fields = "email", targetClass = "Acme\ManagementBundle\Entity\User", message="Email already_used")
*/
class UserOperator extends User
{
/**
* @ORM\Id
* @ORM\Column(type="integer")
* @ORM\GeneratedValue(strategy="AUTO")
*/
protected $id;
/**
* @ORM\PrePersist
*/
public function setCreatedAtValue()
{
$this->addRole('ROLE_OPERATOR');
}
}
When I try to register, I fill the form, submit, than appears:
当我尝试注册时，我填写表格，提交，然后出现：
Warning: in_array() expects parameter 2 to be array, null given in C:\BitNami\wampstack-
5.4.23-0\frameworks\symfony\vendor\friendsofsymfony\user-
bundle\FOS\UserBundle\Model\User.php line 142
The line 142 is the following:
第 142 行如下：
135 public function addRole($role)
{
$role = strtoupper($role);
if ($role === static::ROLE_DEFAULT) {
return $this;
}
142 if (!in_array($role, $this->roles, true)) {
$this->roles[] = $role;
}
return $this;
}
Don't know because I have this problem since I made an association @ORM\ManyToMany between User and Mission, that is another entity that here doesn't appear. Before this I hadn't this problem.
不知道是因为我有这个问题，因为我在 User 和 Mission 之间建立了 @ORM\ManyToMany 关联，这是这里没有出现的另一个实体。在此之前我没有这个问题。
I use PUGXUser Bundle because it helps to easily manage two different kind of user. The User Entity is in my bundle, extends FosUserBundle..../Model/User.php and is extended by UserOperator and UserGroundStation.
我使用 PUGXUser Bundle 是因为它有助于轻松管理两种不同类型的用户。用户实体在我的包中，扩展了 FosUserBundle..../Model/User.php 并由 UserOperator 和 UserGroundStation 扩展。
The definition of the role is in the FosUserBundle.../Model/User.php:
角色的定义在 FosUserBundle.../Model/User.php 中：
/**
* @var array
*/
protected $roles;
and the costruct is:
和 costruct 是：
public function __construct()
{
$this->roles = array();
}
回答by Victor Bocharsky
Try to use:
尝试使用：
if (is_array($this->roles)) {
if (!in_array($role, $this->roles, true)) {
$this->roles[] = $role;
}
}
回答by FuturWebs
in_array() expects parameter 2 to be array, null given
in_array() expects parameter 2 to be array, null given
For me, i solved this problem just with parent::__construct(); on my entity
对我来说，我解决了这个问题parent::__construct()；在我的实体上
public function __construct()
{
parent::__construct();
}
回答by Netzelch
You can code it in one line... nessesary if an array not always exists
您可以在一行中对其进行编码......如果数组不总是存在的话
if ( is_array($maybe_array) AND in_array($needle, $maybe_array) ) {...
because of the handling of the AND-clause your in_array will not be proved if is_array is false.
由于处理 AND 子句，如果 is_array 为假，则不会证明 in_array 。
回答by B.K
It can also help to first check if the array is not empty. For example:
它还可以帮助首先检查数组是否为空。例如：
if (!empty($this->roles) && !in_array($role, $this->roles, true))
回答by Mohd Abdul Baquee
/*Item's lists */
$items = array('Apple', 'Banana', 'Cherry', 'Coconut', 'Guava', 'Lemon', 'Mango');
/*Fruit's lists to be search in Items */
$fruits = array('Apple', 'Coconut', 'Mango');
foreach ($items as $item) {
if (in_array($item, $fruits)) {
$checked = "checked";
}
else{
$checked = "unchecked";
}
echo '< input type="checkbox" name="checkboxes[]"' . $checked . ' />';
}
