在 C++ 中使用 Boost 生成 UUID 的示例
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Example of UUID generation using Boost in C++
提问by Nikola
I want to generate just random UUID's, as it is just important for instances in my program to have unique identifiers. I looked into Boost UUID, but I can't manage to generate the UUID because I don't understand which class and method to use.
我只想生成随机的 UUID，因为我的程序中的实例具有唯一标识符非常重要。我查看了Boost UUID，但我无法生成 UUID，因为我不明白要使用哪个类和方法。
I would appreciate if someone could give me any example of how to achieve this.
如果有人能给我任何如何实现这一目标的例子，我将不胜感激。
回答by Georg Fritzsche
A basic example:
一个基本的例子：
#include <boost/uuid/uuid.hpp> // uuid class
#include <boost/uuid/uuid_generators.hpp> // generators
#include <boost/uuid/uuid_io.hpp> // streaming operators etc.
int main() {
boost::uuids::uuid uuid = boost::uuids::random_generator()();
std::cout << uuid << std::endl;
}
Example output:
示例输出：
7feb24af-fc38-44de-bc38-04defc3804de
7feb24af-fc38-44de-bc38-04defc3804de
回答by Nikko
The answer of Georg Fritzsche is ok but maybe a bit misleading. You should reuse the generator if you need more than one uuid. Maybe it's clearer this way:
Georg Fritzsche 的回答是可以的，但可能有点误导。如果您需要多个 uuid，您应该重用生成器。也许这样更清楚：
#include <iostream>
#include <boost/uuid/uuid.hpp> // uuid class
#include <boost/uuid/uuid_generators.hpp> // generators
#include <boost/uuid/uuid_io.hpp> // streaming operators etc.
int main()
{
boost::uuids::random_generator generator;
boost::uuids::uuid uuid1 = generator();
std::cout << uuid1 << std::endl;
boost::uuids::uuid uuid2 = generator();
std::cout << uuid2 << std::endl;
return 0;
}
