仅针对 bash 中的一行禁止 `set -v` / `set -x` 日志记录
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StackOverFlow
Suppress `set -v` / `set -x` logging only for a single line in bash
提问by Monster Hunter
I'm writing a .sh script like the following:
我正在编写一个 .sh 脚本，如下所示：
echo script started
./some_command > output_file
echo script ended
I'd like the output to be the following:
我希望输出如下：
script started
./some_command > output_file
script ended
I've tried set -v, set +vbut it didn't work properly,
is there anything similar to @echoin batch?
我试过了set -v，set +v但它不能正常工作，
有没有类似于@echo批处理的东西？
Thanks
谢谢
采纳答案by Gilles Quenot
This does what you'd like :
这做你想要的：
#!/bin/bash
echo "script started"
echo "./some_command > output_file"
./some_command > output_file
echo "script ended"
回答by beroe
Using bash -xfrom the comment by @TopGunCoder:
使用bash -x@TopGunCoder 的评论：
#!/usr/bin/env bash -x
echo + echo /Users/myuser/scripts/tbash.sh started
+ ls
[...my directory listing...]
+ pwd
/Users/myuser
+ ./some_command
[the output of "some command"]
+ date
Wed Sep 25 17:06:25 PDT 2013
+ echo /Users/myuser/scripts/tbash.sh ended
started > /dev/null
ls
pwd
./some_command > output_file
date
echo ##代码## ended > /dev/null
The OUTPUT is each command followed by its result:
OUTPUT 是每个命令后跟其结果：
##代码##回答by TopGunCoder
Instead of using echojust replace it with #that way echo isn't displayed and you still get some feedback
而不是使用echo只是用#这种方式替换它，回声不会显示，你仍然会得到一些反馈
