Python 在 matplotlib 中更改 X（时间，而不是数字）频率上的滴答频率
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Change tick frequency on X (time, not number) frequency in matplotlib
提问by Kensg
My pythonplot data only show 2 points on x axis.
我的python绘图数据仅在 x 轴上显示 2 个点。
I would like to have more, but don't know how.
我想要更多，但不知道如何。
x = [ datetime.datetime(1900,1,1,0,1,2),
datetime.datetime(1900,1,1,0,1,3),
...
] # ( more than 1000 elements )
y = [ 34, 33, 23, ............ ]
plt.plot( x, y )
The X axis only shows 2 points of interval. I tried to use .xticksbut didn't work for X axis.
It gave the below error:
X 轴仅显示 2 个间隔点。我尝试使用.xticks但不适用于 X 轴。它给出了以下错误：
TypeError: object of type 'datetime.datetime' has no len()
回答by Sebastian
Whatever reason it is you are getting 2 ticks only by default, you can fix it (customise it) by changing the ticker locator using a date locator.
无论是什么原因，默认情况下您只能获得 2 个刻度，您可以通过使用日期定位器更改代码定位器来修复它（自定义它）。
import matplotlib.pyplot as plt
import matplotlib.dates as mdates
x = [ datetime.datetime(1900,1,1,0,1,2),
datetime.datetime(1900,1,1,0,1,3),
...
] # ( more than 1000 elements )
y = [ 34, 33, 23, ............ ]
fig = plt.figure()
ax = fig.add_subplot(1,1,1)
plt.plot( x, y )
ax.xaxis.set_major_locator(mdates.MinuteLocator(interval=15)) #to get a tick every 15 minutes
ax.xaxis.set_major_formatter(mdates.DateFormatter('%H:%M')) #optional formatting
You have several locators (for example: DayLocator, WeekdayLocator, MonthLocator, etc.) read about it in the documentation:
您在文档中阅读了多个定位器（例如：DayLocator、WeekdayLocator、MonthLocator 等）：
http://matplotlib.org/api/dates_api.html
http://matplotlib.org/api/dates_api.html
But maybe this example will help more:
但也许这个例子会更有帮助：
