C++ 将 long 转换为 char* const
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Convert long to char* const
提问by devnull
What is the right way to convert longto char* constin C++?
什么是转换正确的方式long来char* const在C ++？
EDIT:
编辑：
long l = pthread_self();
ThirdPartyFunction("Thread_Id_"+l); //Need to do this
ThirdPartyFunction(char* const identifierString)
{}
回答by Etienne de Martel
EDIT: The "proper" way to convert an integer to a string, in C++, is to use a stringstream. For instance:
编辑：在 C++ 中将整数转换为字符串的“正确”方法是使用字符串流。例如：
#include <sstream>
std::ostringstream oss;
oss?<< "Thread_Id_" << l;
ThirdPartyFunction(oss.str().c_str());
Now, that probably won't be the "fastest" way (streams have some overhead), but it's simple, readable, and more importantly, safe.
现在，这可能不是“最快”的方式（流有一些开销），但它简单、可读，更重要的是，安全。
OLD ANSWER BELOW
下面的旧答案
Depends on what you mean by "convert".
取决于你所说的“转换”是什么意思。
To convert the long's contents to a pointer:
要将long的内容转换为指针：
char * const p = reinterpret_cast<char * const>(your_long);
To "see" the longas an array of chars:
要“看到” slong的数组char：
char * const p = reinterpret_cast<char * const>(&your_long);
To convert the longto a string:
将 转换long为 a string：
std::ostringstream oss;
oss << your_long;
std::string str = oss.str();
// optionaly:
char * const p = str.c_str();
回答by bonnyz
Another possibile "pure" solution is to use snprintf
另一种可能的“纯”解决方案是使用snprintf
long number = 322323l;
char buffer [128];
int ret = snprintf(buffer, sizeof(buffer), "%ld", number);
char * num_string = buffer; //String terminator is added by snprintf
回答by Michael J
long l=0x7fff0000; // or whatever
char const *p = reinterpret_cast<char const *>(l);
