Android 使用参数进行改造和 GET

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时间:2020-08-20 07:47:53  来源:igfitidea点击:

Retrofit and GET using parameters

androidgetretrofit

提问by Perry Hoekstra

I am trying to send a request to the Google GeoCode API using Retrofit. The service interface looks like this:

我正在尝试使用 Retrofit 向 Google GeoCode API 发送请求。服务接口如下所示:

public interface FooService {    
    @GET("/maps/api/geocode/json?address={zipcode}&sensor=false")
    void getPositionByZip(@Path("zipcode") int zipcode, Callback<String> cb);
}

When I call the service:

当我打电话给服务时:

OkHttpClient okHttpClient = new OkHttpClient();

RestAdapter restAdapter = new RestAdapter.Builder().setEndpoint(Constants.GOOGLE_GEOCODE_URL).setClient(new OkClient(okHttpClient)).build();

FooService service = restAdapter.create(FooService.class);

service.getPositionByZip(zipCode, new Callback<String>() {
    @Override public void success(String jsonResponse, Response response) {
       ...
    }
@Override public void failure(RetrofitError retrofitError) {
    }
});

I receive the following stacktrace:

我收到以下堆栈跟踪:

06-07 13:18:55.337: E/AndroidRuntime(3756): FATAL EXCEPTION: Retrofit-Idle
06-07 13:18:55.337: E/AndroidRuntime(3756): Process: com.marketplacehomes, PID: 3756
06-07 13:18:55.337: E/AndroidRuntime(3756): java.lang.IllegalArgumentException: FooService.getPositionByZip: URL query string "address={zipcode}&sensor=false" must not have replace block.
06-07 13:18:55.337: E/AndroidRuntime(3756):     at retrofit.RestMethodInfo.methodError(RestMethodInfo.java:120)
06-07 13:18:55.337: E/AndroidRuntime(3756):     at retrofit.RestMethodInfo.parsePath(RestMethodInfo.java:216)
06-07 13:18:55.337: E/AndroidRuntime(3756):     at retrofit.RestMethodInfo.parseMethodAnnotations(RestMethodInfo.java:162)
06-07 13:18:55.337: E/AndroidRuntime(3756):     at 

I took a look at the StackOverflow question: Retrofit: multiple query parameters in @GET command?but it did not seem applicable.

我看了一下 StackOverflow 的问题:Retrofit: multiple query parameters in @GET command? 但它似乎并不适用。

I took the code pretty much verbatim from here: http://square.github.io/retrofit/so I am a bit of a loss to understand the issue.

我从这里逐字地获取了代码:http: //square.github.io/retrofit/,所以我对理解这个问题有点茫然。

Thoughts?

想法?

回答by Bart Kiers

AFAIK, {...}can only be used as a path, not inside a query-param. Try this instead:

AFAIK,{...}只能用作路径,不能用作查询参数。试试这个:

public interface FooService {    

    @GET("/maps/api/geocode/json?sensor=false")
    void getPositionByZip(@Query("address") String address, Callback<String> cb);
}

If you have an unknown amount of parameters to pass, you can use do something like this:

如果您有未知数量的参数要传递,您可以使用以下方法:

public interface FooService {    

    @GET("/maps/api/geocode/json")
    @FormUrlEncoded
    void getPositionByZip(@FieldMap Map<String, String> params, Callback<String> cb);
}

回答by madhu527

@QueryMapworked for me instead of FieldMap

@QueryMap为我工作而不是 FieldMap

If you have a bunch of GET params, another way to pass them into your url is a HashMap.

如果您有一堆 GET 参数,另一种将它们传递到您的 url 的方法是HashMap.

class YourActivity extends Activity {

private static final String BASEPATH = "http://www.example.com";

private interface API {
    @GET("/thing")
    void getMyThing(@QueryMap Map<String, String> params, new Callback<String> callback);
}

public void onCreate(Bundle savedInstanceState) {
   super.onCreate(savedInstanceState);
   setContentView(R.layout.your_layout);

   RestAdapter rest = new RestAdapter.Builder().setEndpoint(BASEPATH).build();
   API service = rest.create(API.class);

   Map<String, String> params = new HashMap<String, String>();
   params.put("key1", "val1");
   params.put("key2", "val2");
   // ... as much as you need.

   service.getMyThing(params, new Callback<String>() {
       // ... do some stuff here.
   });
}
}

The URL called will be http://www.example.com/thing/?key1=val1&key2=val2

调用的 URL 将是http://www.example.com/thing/?key1=val1&key2=val2

回答by TheIT

I also wanted to clarify that if you have complex url parameters to build, you will need to build them manually. ie if your query is example.com/?latlng=-37,147, instead of providing the lat and lng values individually, you will need to build the latlng string externally, then provide it as a parameter, ie:

我还想澄清一下,如果您要构建复杂的 url 参数,则需要手动构建它们。即,如果您的查询是example.com/?latlng=-37,147,而不是单独提供 lat 和 lng 值,您将需要在外部构建 latlng 字符串,然后将其作为参数提供,即:

public interface LocationService {    
    @GET("/example/")
    void getLocation(@Query(value="latlng", encoded=true) String latlng);
}

Note the encoded=trueis necessary, otherwise retrofit will encode the comma in the string parameter. Usage:

注意encoded=true是必要的,否则改造将在字符串参数中编码逗号。用法:

String latlng = location.getLatitude() + "," + location.getLongitude();
service.getLocation(latlng);

回答by Hitesh Sahu

Complete working example in Kotlin, I have replaced my API keys with 1111...

Kotlin 中的完整工作示例,我已经用 1111 替换了我的 API 密钥...

        val apiService = API.getInstance().retrofit.create(MyApiEndpointInterface::class.java)
        val params = HashMap<String, String>()
        params["q"] =  "munich,de"
        params["APPID"] = "11111111111111111"

        val call = apiService.getWeather(params)

        call.enqueue(object : Callback<WeatherResponse> {
            override fun onFailure(call: Call<WeatherResponse>?, t: Throwable?) {
                Log.e("Error:::","Error "+t!!.message)
            }

            override fun onResponse(call: Call<WeatherResponse>?, response: Response<WeatherResponse>?) {
                if (response != null && response.isSuccessful && response.body() != null) {
                    Log.e("SUCCESS:::","Response "+ response.body()!!.main.temp)

                    temperature.setText(""+ response.body()!!.main.temp)

                }
            }

        })