javascript 未捕获的类型错误:无法读取 null 的属性“样式”

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时间:2020-10-27 01:24:49  来源:igfitidea点击:

Uncaught TypeError: Cannot read property 'style' of null

javascript

提问by Dymond

I have this function that reads coordination from a XML file, the function works fine when its loose in the window. but when I put it inside a function, then I get the error. Cannot read property 'style' of null.on row 127.

我有这个从 XML 文件读取协调的函数,当它在窗口中松动时,该函数工作正常。但是当我把它放在一个函数中时,我得到了错误。Cannot read property 'style' of null.在第 127 行。

The row 127 is

第 127 行是

document.getElementById(id).style.top=Ynod;

Any ideas ?

有任何想法吗 ?

var main = (function () {

    var id=Math.floor((Math.random()*1000000)+1);


    document.getElementById("add-new-sticker-btn").addEventListener("click", function(){
        id += 1;
        console.log(id);
        add_sticker(""); /**"" removes undefined "*/

        var xmlhttp;
        xmlhttp=new XMLHttpRequest();
        xmlhttp.open("POST","/project2/php/insert.php",true); /*Search way... JS to javaScript*/
        xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded");
        xmlhttp.send("textBoxID="+id);
    });


    function run() {
        readXml();
    }

    function readXml() {
        var xmlhttp;
        xmlhttp = new XMLHttpRequest();
        xmlhttp.open("get", 'xml/stickers.xml', false);
        xmlhttp.send();
        var myXML = xmlhttp.responseXML;
        stickers = myXML.getElementsByTagName("sticker");

        for (i = 0; i < stickers.length; i++) {
            var idNod = (stickers[i].getElementsByTagName("id")[0].childNodes[0].nodeValue); /*Get the ID*/
            var id = idNod;
            var textNod = (stickers[i].getElementsByTagName("text")[0].childNodes[0].nodeValue); /* Text*/
            add_sticker(textNod); /*Call creator function*/

            var Xnod = (stickers[i].getElementsByTagName("x")[0].childNodes[0].nodeValue) + 'px'; /*Get the x position Add PX for pixel*/
            var Ynod = (stickers[i].getElementsByTagName("y")[0].childNodes[0].nodeValue) + 'px'; /*Get the y position*/
            var Znod = (stickers[i].getElementsByTagName("z")[0].childNodes[0].nodeValue); /*Get the y position*/
            console.log(Ynod) // Gives correct Y and X
            console.log(Xnod)

            document.getElementById(id).style.top = Ynod;
            document.getElementById(id).style.left = Xnod;
            document.getElementById(id).style.zIndex = Znod;
        }
    }

    window.addEventListener("load", run);
    return {};
}());

回答by JimCresswell

idNod is undefined, make sure there are elements in stickers and try printing stickers[i].getElementsByTagName("id")[0].childNodes to the console.

idNod 未定义,请确保贴纸中有元素并尝试将贴纸 [i].getElementsByTagName("id")[0].childNodes 打印到控制台。

回答by Dymond

Okej I found the problem my self. I was calling a global variable var id = idNod;If I changed the var id = idNod;to only id=idNodeverything worked :)

好的,我自己发现了这个问题。我正在调用一个全局变量 varid = idNod;如果我将其更改var id = idNod;为仅id=idNod一切正常:)