在 Scala 中从 Array[String] 转换为 Seq[String]
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Converting from Array[String] to Seq[String] in Scala
提问by ps0604
In the following Scala code I attempt to convert from a String that contains elements separated by "|" to a sequence Seq[String]. However the result is a WrappedArray of characters. How to make this work?
在以下 Scala 代码中，我尝试从包含由“|”分隔的元素的字符串进行转换 到一个序列Seq[String]。然而，结果是一个 WrappedArray 字符。如何使这项工作？
val array = "t1|t2".split("|")
println(array.toSeq)
results in:
结果是：
WrappedArray(t, 1, |, t, 2)
What I need is:
我需要的是：
Seq(t1,t2)
回答by rogue-one
The below works. ie split by pipe character ('|') instead of pipe string ("|").
since split("|")calls overloaded definitionthat takes an regex string where pipe is a meta-character. This gets you the incorrect result as shown in the question.
下面的作品。即由管道字符（'|'）而不是管道字符串（“|”）分割。因为split("|")调用了采用正则表达式字符串的重载定义，其中管道是元字符。如问题所示，这会为您提供不正确的结果。
scala> "t1|t2".split('|').toSeq
res10: Seq[String] = WrappedArray(t1, t2)
