php 使用 CURL 将 JSON 数据发布到 API
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Posting JSON data to API using CURL
提问by ArkNet
When I'm posting jsondata to API using curl- I'm not getting any output. I would like to send email invitation to recipient.
当我json使用 API发布数据时curl- 我没有得到任何输出。我想向收件人发送电子邮件邀请。
$url_send ="http://api.address.com/SendInvitation?";
$str_data = json_encode($data);
function sendPostData ($url, $post) {
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_POSTFIELDS, http_build_query($post));
return curl_exec($ch);
}
And here is JSON$str_data
这里是 JSON$str_data
[
{
"authorizedKey" : "abbad35c5c01-xxxx-xxx",
"senderEmail" : "[email protected]",
"recipientEmail" : "[email protected]",
"comment" : "Invitation",
"forceDebitCard" : "false"
}
]
And calling function:
并调用函数：
$response = sendPostData($url_send, $str_data);
This is the API: https://api.payquicker.com/Help/Api/POST-api-SendInvitation
这是 API：https: //api.payquicker.com/Help/Api/POST-api-SendInvitation
回答by Dylan Holmes
Try adding curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
And changing http_build_query($post)to $post
尝试添加curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
并更改http_build_query($post)为$post
The implementation:
实施：
<?php
$data = array(
"authorizedKey" => "abbad35c5c01-xxxx-xxx",
"senderEmail" => "[email protected]",
"recipientEmail" => "[email protected]",
"comment" => "Invitation",
"forceDebitCard" => "false"
);
$url_send ="http://api.payquicker.com/api/SendInvitation?authorizedKey=xxxxx";
$str_data = json_encode($data);
function sendPostData($url, $post){
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST");
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_POSTFIELDS,$post);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
$result = curl_exec($ch);
curl_close($ch); // Seems like good practice
return $result;
}
echo " " . sendPostData($url_send, $str_data);
?>
The response I get is:
我得到的回应是：
{"success":false,"errorMessage":"Object reference not set to an instance of an object.","status":"N/A"}
But maybe it will work with valid data....
但也许它适用于有效数据....
Edit:For posting xml, it's the same as on their site, except in a string:
编辑：对于发布 xml，它与在他们的网站上相同，除了在字符串中：
$xml = '
<SendInvitationRequest xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/PQApi.Models">
<authorizedKey>80c587b9-caa9-4e56-8750-a34b17dba0a2</authorizedKey>
<comment>sample string 4</comment>
<forceDebitCard>true</forceDebitCard>
<recipientEmail>sample string 3</recipientEmail>
<senderEmail>sample string 2</senderEmail>
</SendInvitationRequest>';
Then:
然后：
sendPostData($url_send, $xml)
回答by mousumi deb
You have to add header:
您必须添加标题：
$headers= array('Accept: application/json','Content-Type: application/json');
And:
和：
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
Otherwise ...
除此以外 ...
HTTP Status 415 - Unsupported Media Type
HTTP 状态 415 - 不支持的媒体类型
... may happen.
……可能会发生。
回答by Sankar Palani
You don't need to add headers as you already do json_encode.
just print_r (curl_getinfo($ch));and see the content type info in it.
您不需要像已经做的那样添加标题json_encode。只需print_r (curl_getinfo($ch));查看其中的内容类型信息。
