Javascript Array.sort() 不能正确排序数字
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Array.sort() doesn't sort numbers correctly
提问by Some Guy
In Chrome 14, and Firefox 5 (haven't tested other browsers), the following code doesn't sort the numbers correctly:
在 Chrome 14 和 Firefox 5（尚未测试其他浏览器）中，以下代码未正确对数字进行排序：
<script>
a = new Array();
a.push(10);
a.push(60);
a.push(20);
a.push(30);
a.push(100);
document.write(a.sort())
</script>
It returns 10,100,20,30,60
它返回 10,100,20,30,60
I've tried different numbers, and it always acts as if the 0s aren't there and sorts the numbers correctly otherwise. Anyone know why?
我尝试了不同的数字，它总是表现得好像 0 不存在一样，否则会正确地对数字进行排序。有谁知道为什么？
采纳答案by Jason S
I've tried different numbers, and it always acts as if the 0s aren't there and sorts the numbers correctly otherwise. Anyone know why?
我尝试了不同的数字，它总是表现得好像 0 不存在一样，否则会正确地对数字进行排序。有谁知道为什么？
You're getting a lexicographical sort (e.g. convert objects to strings, and sort them in dictionary order), which is the default sort behavior in Javascript:
你得到了一个字典排序（例如将对象转换为字符串，并按字典顺序对它们进行排序），这是 Javascript 中的默认排序行为：
https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/sort
https://developer.mozilla.org/en/JavaScript/Reference/Global_Objects/Array/sort
array.sort([compareFunction])Parameters
compareFunction
Specifies a function that defines the sort order. If omitted, the array is sorted lexicographically (in dictionary order) according to the string conversion of each element.
array.sort([compareFunction])参数
比较函数
指定定义排序顺序的函数。如果省略，则根据每个元素的字符串转换按字典顺序（按字典顺序）对数组进行排序。
In the ECMAscript specification (the normative reference for the generic Javascript), ECMA-262, 3rd ed., section 15.4.4.11, the default sort order is lexicographical, although they don't come out and say it, instead giving the steps for a conceptual sort function that calls the given compare function if necessary, otherwise comparing the arguments when converted to strings:
在 ECMAscript 规范（通用 Javascript 的规范参考）中，ECMA-262，第 3 版。, 第 15.4.4.11 节，默认排序顺序是字典序的，虽然他们不出来说出来，而是给出概念排序函数的步骤，该函数在必要时调用给定的比较函数，否则在转换为字符串时比较参数：
13. If the argument comparefn is undefined, go to step 16.
14. Call comparefn with arguments x and y.
15. Return Result(14).
16. Call ToString(x).
17. Call ToString(y).
18. If Result(16) < Result(17), return ?1.
19. If Result(16) > Result(17), return 1.
20. Return +0.
回答by Joseph Marikle
回答by Nick Husher
The default sort for arrays in Javascript is an alphabetical search. If you want a numerical sort, try something like this:
Javascript 中数组的默认排序是按字母顺序搜索。如果您想要数字排序，请尝试以下操作：
var a = [ 1, 100, 50, 2, 5];
a.sort(function(a,b) { return a - b; });
回答by Julien Lafont
You can use a sort function :
您可以使用排序功能：
var myarray=[25, 8, 7, 41]
myarray.sort( function(a,b) { return b - a; } );
// 7 8 25 41
Look at http://www.javascriptkit.com/javatutors/arraysort.shtml
回答by Samir Adel
try this:
尝试这个：
a = new Array();
a.push(10);
a.push(60);
a.push(20);
a.push(30);
a.push(100);
a.sort(Test)
document.write(a);
function Test(a,b)
{
return a > b ? true : false;
}
