类路径在 linux 下不起作用
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Classpath does not work under linux
提问by sproketboy
Anyone have an idea why this command works fine in Windows but in Linux I get a ClassNotFoundException game.ui.Main
任何人都知道为什么这个命令在 Windows 中工作正常，但在 Linux 中我得到一个 ClassNotFoundException game.ui.Main
java -cp ".;lib/*" game.ui.Main -Xms64m -Xmx128m
my folder structure looks like this: lib/ - Jars game/ - Class files
我的文件夹结构如下所示：lib/ - Jars game/ - Class files
This is the latest Java 6.
这是最新的 Java 6。
采纳答案by peter.murray.rust
The classpath syntax is OS-dependent. From Wikipedia:
类路径语法取决于操作系统。来自维基百科：
Being closely associated with the file system, the command-line Classpath syntax depends on the operating system. For example:
on all Unix-like operating systems (such as Linux and Mac OS X), the directory structure has a Unix syntax, with separate file paths separated by a colon (":").
on Windows, the directory structure has a Windows syntax, and each file path must be separated by a semicolon (";").
This does not apply when the Classpath is defined in manifest files, where each file path must be separated by a space (" "), regardless of the operating system.
由于与文件系统密切相关，命令行类路径语法取决于操作系统。例如：
在所有类 Unix 操作系统（如 Linux 和 Mac OS X）上，目录结构采用 Unix 语法，用冒号（“:”）分隔单独的文件路径。
在 Windows 上，目录结构具有 Windows 语法，每个文件路径必须用分号 (";") 分隔。
这不适用于在清单文件中定义类路径的情况，其中每个文件路径都必须用空格 (" ") 分隔，而与操作系统无关。
回答by Mikel
Try changing the semi-colon to a colon.
尝试将分号更改为冒号。
The CLASSPATH separator is platform dependent, and is the same as the character returned by java.io.File.pathSeparatorChar.
CLASSPATH 分隔符取决于平台，并且与java.io.File.pathSeparatorChar返回的字符相同。
回答by pinkston00
Paths are important too when using classpaths in scripts meant to be run on both platforms: Windows (i.e. cygwin) and Linux. When I do this I include a function like this for the classpath. The 'cygpath' command with the '-w' option converts paths to Windows-style paths. So in this example "/home/user/lib/this.jar" would be converted to something like "C:\Cygwin\home\user\lib\this.jar"
在打算在两个平台上运行的脚本中使用类路径时，路径也很重要：Windows（即 cygwin）和 Linux。当我这样做时，我为类路径包含了一个这样的函数。带有 '-w' 选项的 'cygpath' 命令将路径转换为 Windows 样式的路径。所以在这个例子中“/home/user/lib/this.jar”将被转换为类似“C:\Cygwin\home\user\lib\this.jar”的内容
#!/bin/bash
function add_java_classpath() {
local LOCAL1=
if [ "$OSTYPE" == cygwin ]; then
LOCAL1="$(cygpath -C ANSI -w $LOCAL1)"
fi
if [ -z "$JAVA_CLASSPATH" ]; then
JAVA_CLASSPATH="$LOCAL1"
elif [ "$OSTYPE" != cygwin ]; then
JAVA_CLASSPATH="${JAVA_CLASSPATH}:$LOCAL1"
else
JAVA_CLASSPATH="${JAVA_CLASSPATH};$LOCAL1"
fi
}
add_java_classpath /home/user/lib/this.jar
add_java_classpath /usr/local/lib/that/that.jar
java -cp "${JAVA_CLASSPATH}" package.Main $@
回答by Wender
Windows:
视窗：
java -cp file.jar;dir/* my.app.ClassName
java -cp file.jar;dir/* my.app.ClassName
Linux:
Linux：
java -cp file.jar:dir/* my.app.ClassName
java -cp file.jar:dir/* my.app.ClassName
Remind:
提醒：
- Windows path separator is
; - Linux path separator is
: - In Windows if cp argument does not contains white space, the quotes is optional
- Windows 路径分隔符是
; - Linux路径分隔符是
: - 在 Windows 中，如果 cp 参数不包含空格，则引号是可选的
