<br /><b>注意</b>:<b>7</b>行<b>C:\xampp\htdocs\form2\edit.php</b>中的未定义变量:user_name <br
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<br /><b>Notice</b>: Undefined variable: user_name in <b>C:\xampp\htdocs\form2\edit.php</b> on line <b>7</b><br />
提问by rakesh suryan
<!doctype html>
<html>
<head>
<title></title></head>
<body>
<form action="#" method="POST" enctype="multipart/form-data">
<input type="text" name="usname" value = "<?=$user_name;?>"/>
<input type="password" name="psd" value = "<?=$pass_word;?>" />
<input type="textarea" name="addrs" value = "<?=$address;?>">
<input type="hidden" name="id" value = "<?=$id?>"/>
<input type="submit" name="submit" value="submit"/>
</form>
<?php
if(isset($_POST['submit'])){
$sql= "Update form set user_name='".$_POST['usname']."',
pass_word='".$_POST['psd']."',
address='".$_POST['addrs']."'
where id='".$_GET['id']."'
";
$result=mysql_query($sql);
if($result)
{
echo"data is succesfully data insert";
header("location:login.php");
}else
{echo"";}
}
$id='';
$user_name='';
$pass_word='';
$address='';
$host="localhost";
$username="root";
$password="";
$db="form2";
$con=mysql_connect($host,$username,$password);
if(isset($_GET['id']))
{
echo $query = "select id,user_name,pass_word,address from form where id=".$_GET['id'];
mysql_select_db($db,$con);
echo $result=mysql_query($query);
if($result){
while($row= mysql_fetch_array($result))
$id=$row['id'];
$user_name=$row['user_name'];
$pass_word=$row['pass_word'];
$address=$row['address'];
}
}
?>
</body>
</html>
Notice: Undefined variable: user_name in C:\xampp\htdocs\form2\edit.phpon line 7
注意:未定义变量:user_name in C:\xampp\htdocs\form2\edit.php第7行
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Notice: Undefined variable: address in C:\xampp\htdocs\form2\edit.phpon line 9
submit
注意:未定义变量:地址在C:\xampp\htdocs\form2\edit.php第9行
提交
i am create a edit.php and update the values
我正在创建一个 edit.php 并更新值
I'm running a PHP script, and maintain getting errors like:
我正在运行一个 PHP 脚本,并保持收到如下错误:
回答by Brijal Savaliya
If you are using some variable then please check if its set or not
如果您正在使用某个变量,请检查它是否已设置
<?=$user_name;?> you need to chnage to <?=(isset($user_name)?$user_name:""?> and same for others.